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leetcode:Rotate Array 【Java】

2016-03-07 16:17 537 查看
一、问题描述

Rotate an array of n elements to the right by k steps.

For example, with n = 7 and k = 3, the array
[1,2,3,4,5,6,7]
is
rotated to
[5,6,7,1,2,3,4]
.

Note:

Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
二、问题分析

注意循环一圈后回到原出发点的情况,例如,数组长度为6,k=2:0-->2-->4-->0,会造成只有下标为0,2,4,的几个数再不停交换。

三、算法代码

public class Solution {
    public void rotate(int[] nums, int k) {
        int index = 0;
        int distance = 0;
        int cur = 0;
        for (int i = 0; i < nums.length; i++){
            int next = (index+k)%nums.length;
            int temp = nums[next];
            nums[next] = nums[cur];
            nums[cur] = temp;
            index = next;

            distance=(distance+k)%nums.length;
            if (distance == 0){
                index = (index+1)%nums.length;
                cur = index;
            }
        }
    
    
    }
}
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