golang捕获ctrl+c退出程序

在golang当中如何捕获ctrl+c命令，让程序有序的的退出？

首先测试一段golang代码,捕获SIGINT和SIGKILL

c := make(chan os.Signal, 1)
signal.Notify(c, os.Interrupt, os.Kill)

s := <-c
fmt.Println("Got signal:", s)

在多goroutines当中如何退出？我们假设有一个生产者，一个消费者，这个时候应该让生产者去捕获消息，关闭channel，生产者退出；消费者感知到channel关闭，消费者退出。

package main

import (
"time"
"fmt"
"os"
"os/signal"
"sync"
)

var c chan os.Signal
var msgQueue chan *string
var wg sync.WaitGroup

func Producer(){
i := 0
LOOP:
for{
select {
case s := <-c:
fmt.Println()
fmt.Println("Producer | get", s)
break LOOP
default:
}

i ++
s := fmt.Sprintf("work-%d", i)
fmt.Println("Producer | produce", s)
msgQueue <- &s
time.Sleep(500 * time.Millisecond)
}

close(msgQueue)
fmt.Println("Producer | close channel, exit")
wg.Done()
}

func Consumer(){
for m := range msgQueue{
if m != nil{
fmt.Println("Consumer | consume", *m)
}else{
fmt.Println("Consumer | channel closed")
break
}
}
fmt.Println("Consumer | exit")
wg.Done()
}

func main(){
c = make(chan os.Signal, 1)
msgQueue = make(chan *string, 1000)
signal.Notify(c, os.Interrupt, os.Kill)

//pruducer
wg.Add(1)
go Producer()

//consumer
wg.Add(1)
go Consumer()

wg.Wait()
}

运行结果：

Producer | produce work-1
Consumer | consume work-1
Producer | produce work-2
Consumer | consume work-2
Producer | produce work-3
Consumer | consume work-3
Producer | produce work-4
Consumer | consume work-4

Producer | get interrupt
Producer | close channel, exit
Consumer | exit

参考：

1. http://www.oschina.net/translate/golang-graceful-stop?lang=eng