画柱状图Java
2016-02-16 13:37
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样例输入:
THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG.
THIS IS AN EXAMPLE TO TEST FOR YOUR
HISTOGRAM PROGRAM.
HELLO!
样例输出:
*
*
* *
* * * *
* * * *
* * * * * *
* * * * * * * * * *
* * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * * * * * * * * * *
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
题目的意思是从命令行输入一个大写的字符串,求一个字符出现的频率,画出来。
THE QUICK BROWN FOX JUMPED OVER THE LAZY DOG.
THIS IS AN EXAMPLE TO TEST FOR YOUR
HISTOGRAM PROGRAM.
HELLO!
样例输出:
*
*
* *
* * * *
* * * *
* * * * * *
* * * * * * * * * *
* * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * * * * * * * * * *
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
题目的意思是从命令行输入一个大写的字符串,求一个字符出现的频率,画出来。
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.Arrays; public class Main { public static void main(String[] args) throws NumberFormatException, IOException { BufferedReader read = new BufferedReader(new InputStreamReader( System.in)); int[] a = new int[26]; int tt; for (int i = 0; i < 4; i++) { String str = read.readLine(); for (int j = 0; j < str.length(); j++) { tt = str.charAt(j) - 'A'; if (tt >= 0 && tt <= 25) { a[tt]++; } } } int max = 0; for (int i = 0; i < 26; i++) { if (a[i] > max) { max = a[i]; } } char[][] c = new char[max + 1][51]; for (int i = 0; i < max + 1; i++) { Arrays.fill(c[i], ' '); } for (int i = 0; i < 26; i++) { int h = a[i]; for (int j = 0; j < h; j++) { c[max - 1 - j][i * 2] = '*'; } } for (int i = 0; i < 26; i++) { c[max][i * 2] = (char) ('A' + i); } for (int i = 0; i < max + 1; i++) { String str = String.valueOf(c[i]); while (str.endsWith(" ")) { str = str.substring(0, str.length() - 1); } System.out.println(str); } }
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