Sicily 1790. Single Round Match
2016-01-09 18:53
495 查看
Time Limit: 1 secs, Memory Limit: 32 MB
Description
Association for Couples Match (ACM) is a non-profit organization which is engaged in helping single people to find his/her other half. As November 11th is “Singles Day”, on this day, ACM invites a large group of singles to the party. People round together, chatting with others, and matching partners. There are N gentlemen and M ladies in the party, each gentleman should only match with a lady and vice versa. To memorize the Singles Day, ACM decides to divide people into 11 groups, each group should have the same amount of couples and no people are left without the groups. Can ACM achieve the goal?
Input
The first line of the input is a positive integer T. T is the number of test cases followed. Each test case contains two integer N and M (0<=N, M<=101000), which are the amount of gentlemen and ladies. It is worth notice that N and M are really huge. You are suggested to input the number with string.
Output
Sample Input
3
1 1
11 11
22 11
Sample Output
NO
YES
NO
<( ̄ˇ ̄)/[/b] Just do it!
Description
Association for Couples Match (ACM) is a non-profit organization which is engaged in helping single people to find his/her other half. As November 11th is “Singles Day”, on this day, ACM invites a large group of singles to the party. People round together, chatting with others, and matching partners. There are N gentlemen and M ladies in the party, each gentleman should only match with a lady and vice versa. To memorize the Singles Day, ACM decides to divide people into 11 groups, each group should have the same amount of couples and no people are left without the groups. Can ACM achieve the goal?
Input
The first line of the input is a positive integer T. T is the number of test cases followed. Each test case contains two integer N and M (0<=N, M<=101000), which are the amount of gentlemen and ladies. It is worth notice that N and M are really huge. You are suggested to input the number with string.
Output
For each test case, output “YES” if it is possible to find a way, output “NO” if not.
Sample Input
3
1 1
11 11
22 11
Sample Output
NO
YES
NO
<( ̄ˇ ̄)/[/b] Just do it!
#include <iostream> #include <string> using namespace std; int main() { string boy, girl; int T, Temp; cin >> T; while (T--) { cin >> boy >> girl; if (boy != girl) { cout << "NO" << endl; continue; } Temp = 0; for (int i = boy.size() - 1; i >= 0; i--) { Temp = Temp * 10 + boy[i] - 48; Temp %= 11; } if (Temp == 0) cout << "YES" << endl; else cout << "NO" << endl; } return 0; }
相关文章推荐
- 使用C++实现JNI接口需要注意的事项
- 关于指针的一些事情
- c++ primer 第五版 笔记前言
- share_ptr的几个注意点
- Lua中调用C++函数示例
- Lua教程(一):在C++中嵌入Lua脚本
- Lua教程(二):C++和Lua相互传递数据示例
- C++联合体转换成C#结构的实现方法
- C++高级程序员成长之路
- C++编写简单的打靶游戏
- C++ 自定义控件的移植问题
- C++变位词问题分析
- C/C++数据对齐详细解析
- C++基于栈实现铁轨问题
- C++中引用的使用总结
- 使用Lua来扩展C++程序的方法
- C++中调用Lua函数实例
- Lua和C++的通信流程代码实例
- C与C++之间相互调用实例方法讲解
- 解析C++中派生的概念以及派生类成员的访问属性