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iOS打开外部应用、浏览器

2015-12-30 15:10 471 查看
1:打开Mail

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NSString *recipients = @"mailto:ysy@flyrise.cn?subject=Hello from California!";

NSString *body = @"&body=It is raining in sunny California!";

NSString *email = [NSString stringWithFormat:@"%@%@", recipients, body];

email = [email stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:email]];

2:打电话

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NSString *num = @"110"; //number为号码字符串

NSString *mobileNumber = [NSString stringWithFormat:@"telprompt://%@", num];

NSLog(@"call phone %@;", mobileNumber);

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:mobileNumber]];

注:上面代码触发后,系统会提示用户是否真的要打电话, 电话结束后,会返回至应用程序,

如果将telprompt修改为:tel 后,点击可直接拨打电话, 但电话结束后,不会返回至应用程序

2:打开Safari

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[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.baidu.com"]];

3:打开Messages

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[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"sms://800888"]];

4:打开App Store 某个应用的评价系统

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NSLog(@"%@",[[[SystemGlobalInfo defaultInstance] deviceInfo] applicationId]);

NSString *str = [NSString stringWithFormat: @"itms-apps://ax.itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id=%@",[[[SystemGlobalInfo defaultInstance] deviceInfo] applicationId]];

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:str]];

5:打开App Store 中的某个应用 途中经过Safari

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NSString *appID = @"291586600";

NSString *appUrl = [NSString stringWithFormat:@"http://phobos.apple.com/WebObjects/MZStore.woa/wa/viewSoftware?id=%@&mt=8",appID];

NSURL *appStoreUrl = [NSURL URLWithString:appUrl];

[[UIApplication sharedApplication] openURL:appStoreUrl];

6:打开App Store 中的某个应用 直接跳转

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NSString *urlString = @"http://itunes.apple.com/us/app/ye-wu-xie-zuo-ping-tai/id507704613?mt=8&uo=4";

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]] ;

7:打开谷歌Maps进行搜索

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NSString* searchQuery = @"珠海";

searchQuery = [searchQuery stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];

NSString* urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@", searchQuery];

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];

8:利用OpenUrl打开第三方应用程序

本文释权了打开的方式,很详细.. 地址如下:

http://blog.cnrainbird.com/index.php/2012/06/04/tong_guo_openurl_qi_dong_di_san_fang_app_bing_chuan_can_shu/

这里简单描述一下注意点,

1: A工程 需要打开 B 工程 那么B工程需要在plist文件中 进行UrlType的注册

2:在启动其他第三方应用程序之前,可以通过如下代码判断,应用程序是否已经安装在iPhone中.

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NSURL *url = [NSURL URLWithString:@"AppMessageDemo:11"];

if ([[UIApplication sharedApplication] canOpenURL:url]) {

[[UIApplication sharedApplication] openURL:url];

}else {

[ShareCode Msg:@"没安装"];

}

3: B工程被打开时,请使用如下委托处理打开的消息

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-(BOOL)application:(UIApplication *)application openURL:(NSURL *)url sourceApplication:(NSString *)sourceApplication annotation:(id)annotation

{

NSLog(@"%@",[url path]);

NSLog(@"%@",sourceApplication);

NSLog(@"%@",annotation);

return NO;

}

下面这个委托,也就是微文中提到的委托,已经被苹果弃用

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-(BOOL)application:(UIApplication *)application handleOpenURL:(NSURL *)url

{

NSLog(@"123");

return [WXApi handleOpenURL:url delegate:self];

}

注: sourceApplication 表示 App plist文件中标明的 Bundle identifier

至于返回YES,还是返回NO,似乎没有发生任何事情,待继续考证.

9:为应用设置首选项功能

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