Leetcode 8 - String to Integer (atoi)
2015-12-24 22:25
399 查看
Implement atoi to convert a string to an integer.
Hint:
Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
Requirements for atoi:
The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, takes an optional initial plus or minus sign followed by as many numerical digits as possible, and interprets them as a numerical value.
The string can contain additional characters after those that form the integral number, which are ignored and have no effect on the behavior of this function.
If the first sequence of non-whitespace characters in str is not a valid integral number, or if no such sequence exists because either str is empty or it contains only whitespace characters, no conversion is performed.
If no valid conversion could be performed, a zero value is returned. If the correct value is out of the range of representable values, INT_MAX (2147483647) or INT_MIN (-2147483648) is returned.
细节实现题,主要注意以下几点:
1 - 跳过字符串首的空格;
2 - 判断正负
3 - 考虑整型溢出问题
Hint:
Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
Requirements for atoi:
The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, takes an optional initial plus or minus sign followed by as many numerical digits as possible, and interprets them as a numerical value.
The string can contain additional characters after those that form the integral number, which are ignored and have no effect on the behavior of this function.
If the first sequence of non-whitespace characters in str is not a valid integral number, or if no such sequence exists because either str is empty or it contains only whitespace characters, no conversion is performed.
If no valid conversion could be performed, a zero value is returned. If the correct value is out of the range of representable values, INT_MAX (2147483647) or INT_MIN (-2147483648) is returned.
细节实现题,主要注意以下几点:
1 - 跳过字符串首的空格;
2 - 判断正负
3 - 考虑整型溢出问题
class Solution { public: int myAtoi(string str) { int result = 0; int sign = 1; int i=0; //跳过字符串首的空格 while(str[i]==' ') i++; //判断正负 if(str[i]=='-'){ sign = -1; i++; }else if(str[i]=='+'){ i++; } for(;i<str.length();i++){ if(str[i]<'0' || str[i]>'9') return result*sign; //溢出条件 if(result>INT_MAX/10 || (result==INT_MAX/10 && str[i]-'0'>INT_MAX%10)) return sign==-1?INT_MIN:INT_MAX; result = result*10 + str[i]-'0'; } return result * sign; } };
相关文章推荐
- 使用C++实现JNI接口需要注意的事项
- 关于指针的一些事情
- c++ primer 第五版 笔记前言
- share_ptr的几个注意点
- Lua中调用C++函数示例
- Lua教程(一):在C++中嵌入Lua脚本
- Lua教程(二):C++和Lua相互传递数据示例
- C++联合体转换成C#结构的实现方法
- C++编写简单的打靶游戏
- C++ 自定义控件的移植问题
- C++变位词问题分析
- C/C++数据对齐详细解析
- C++基于栈实现铁轨问题
- C++中引用的使用总结
- 使用Lua来扩展C++程序的方法
- C++中调用Lua函数实例
- Lua和C++的通信流程代码实例
- C与C++之间相互调用实例方法讲解
- 解析C++中派生的概念以及派生类成员的访问属性
- C++ Custom Control控件向父窗体发送对应的消息