oracle中截取某个字符前面和后面的值

create table test
(name varchar2(10));

insert into test values ('2-15');
insert into test values ('2-33');
insert into test values ('2-3');
insert into test values ('12-8');
insert into test values ('12-22');
insert into test values ('12-3');

select name,substr(name,1,instr(name,'-')-1) 前,substr(name,instr(name,'-')+1,length(name)-instr(name,'-')) 后 from test