南邮编程在线编程题十一：指针形参的使用，找数组中的最大最小元素值

max=90, maxPos=2, min=-9, minPos=3

#include <stdio.h>

void Find(int *a, int n, int *max, int *maxPos, int *min, int *minPos)
{
	int i;
	*min = a[0];
	*minPos = 0;
	*max = a[0];
	*maxPos = 0;
	for (i = 0; i < n; ++i) {
		if (a[i] < *min) {
			*min = a[i];
			*minPos = i;
		}
		if (a[i] > *max) {
			*max = a[i];
			*maxPos = i;
		}
	}
}

int main()
{
	int array[10] = {23,45,90,-9,43,90,4,2,-9};
	int max, maxPos, min, minPos;
	Find(array, 10, &max, &maxPos, &min, &minPos);
	printf("max=%d, maxPos=%d, min=%d, minPos=%d\n", max, maxPos, min, minPos);
	return 0;
}