Python中的shape计算矩阵

>>> from numpy import *
>>> import operator
>>> a =mat([[1,2,3],[5,6,9]])
>>> a
matrix([[1, 2, 3],
[5, 6, 9]])

>>> shape(a)
(2, 3)
>>> a.shape[0] #计算行数
2
>>> a.shape[1] #计算列数
3

Examples
--------
>>> np.shape(np.eye(3))
(3, 3)
>>> np.shape([[1, 2]])
(1, 2)
>>> np.shape([0])
(1,)
>>> np.shape(0)
()

>>> a = np.array([(1, 2), (3, 4)], dtype=[('x', 'i4'), ('y', 'i4')])
>>> np.shape(a)
(2,)
>>> a.shape
(2,)