shell 函数参数为数组传递

You cannot pass an array, you can only pass its elements (i.e. the expanded array).

#! /bin/bash
function f() {
a=("$@")
((last_idx=${#a[@]} - 1))
b=${a[last_idx]}
unset a[last_idx]

for i in "${a[@]}" ; do
echo "$i"
done
echo "b: $b"
}

x=("one two" "LAST")
b='even more'

f "${x[@]}" "$b"
echo ===============
f "${x[*]}" "$b"

The other possibility would be to pass the array by name:

#! /bin/bash
function f() {
name=$1[@]
b=$2
a=("${!name}")

for i in "${a[@]}" ; do
echo "$i"
done
echo "b: $b"
}

x=("one two" "LAST")
b='even more'

f x "$b"

http://stackoverflow.com/questions/16461656/bash-how-to-pass-array-as-an-argument-to-a-function