C# 如何将List拆分成多个子集合

网上的例子：问：List<string> list = new List<string>();
for (int i = 1; i < 95; i++)
{
list.Add(i.ToString());
}
如何将list拆分成10个子集合？
答案： List<List<string>> listGroup = new List<List<string>>(); int j = 10; for (int i = 0; i < list1.Count; i += 10) { List<string> cList = new List<string>(); cList = list1.Take(j).Skip(i).ToList(); j +=10; listGroup.Add(cList); }

个人使用中的实例如下： #region 新方法
List<List<hourhistoryrecorditem>> listGroup = new List<List<hourhistoryrecorditem>>(); int j = 500000; for (int i = 0; i < lstVals.Count; i += 500000)//以50万为一组分组 { List<hourhistoryrecorditem> cList = new List<hourhistoryrecorditem>(); cList = lstVals.Take(j).Skip(i).ToList(); j += 500000; listGroup.Add(cList); } for (int i = 0; i < listGroup.Count; i++) { List<hourhistoryrecorditem> list = new List<hourhistoryrecorditem>(); list = listGroup[i]; foreach (hourhistoryrecorditem aItem in list) { int iOffset = 0; DataRow r = dt.NewRow();
r[iOffset++] = DBNull.Value; r[iOffset++] = aItem.CurValue; r[iOffset++] = aItem.MaxValue_; r[iOffset++] = aItem.MinValue; r[iOffset++] = aItem.AvgValue; r[iOffset++] = aItem.ValueFlag; r[iOffset++] = aItem.RecordType; r[iOffset++] = aItem.NodeID; r[iOffset++] = aItem.LogDT; r[iOffset++] = aItem.DataCount; r[iOffset++] = aItem.Increment; r[iOffset++] = aItem.VTopVal; r[iOffset++] = aItem.TopVal; r[iOffset++] = aItem.NormalVal; r[iOffset++] = aItem.LowVal; r[iOffset++] = aItem.VLowVal; r[iOffset++] = aItem.ChargeVal; r[iOffset++] = aItem.IncVTopVal; r[iOffset++] = aItem.IncTopVal; r[iOffset++] = aItem.IncNormalVal; r[iOffset++] = aItem.IncLowVal; r[iOffset++] = aItem.IncVLowVal; r[iOffset++] = aItem.IncChargeVal; r[iOffset++] = aItem.OrgID;
dt.Rows.Add(r);
} TablesBlukInsertOp.BulkToDB(dt, "hourhistoryrecorditem"); dt.Rows.Clear();//执行完插入后，记得清空DataTable }
#endregion

来自为知笔记(Wiz)