Y2K Accounting Bug（二进制+枚举）

E - Y2K Accounting BugTime Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d& %I64uSubmit Status Practice POJ2586Appoint description: System Crawler  (2015-09-28)DescriptionAccounting for Computer Machinists (ACM) has sufferred from the Y2K bug and lost some vital data for preparing annual report for MS Inc. All what they remember is that MS Inc. posted a surplus or a deficit each month of 1999 and each month when MS Inc. posted surplus, the amount of surplus was s and each month when MS Inc. posted deficit, the deficit was d. They do not remember which or howmany months posted surplus or deficit. MS Inc., unlike other companies, posts their earnings for each consecutive 5 months during a year. ACM knows that each of these 8 postings reported a deficit but they do not know how much. The chief accountant is almostsure that MS Inc. was about to post surplus for the entire year of 1999. Almost but not quite. Write a program, which decides whether MS Inc. suffered a deficit during 1999, or if a surplus for 1999 was possible, what is the maximum amount of surplus that they can post.InputInput is a sequence of lines, each containing two positive integers s and d.OutputFor each line of input, output one line containing either a single integer giving the amount of surplus for the entire year, or output Deficit if it is impossible.Sample Input

59 237
375 743
200000 849694
2500000 8000000

Sample Output

116
28
300612
Deficit

题意：

题意真心看不懂，之后看了题解才知道怎么做。他就是说每个月分别只有盈利与亏损两种情况，而还有个附加条件就是1-5,

2-6，3-7,4-8,5,9,6-10,7-11，8-12,都要是亏损的。求在这种情况下的1-12个月总和是大于零的最大值。

AC代码：

#include<iostream>#include<algorithm>#include<cstring>#include<string>#include<cstdio>#include<vector>#include<cmath>using namespace std;#define T 5005#define inf -0x3f3f3f3fint a[12],b[2],c;bool jugde(){for(int i=0;i<=7;++i){if(b[a[i]]+b[a[i+1]]+b[a[i+2]]+b[a[i+3]]+b[a[i+4]]>=0)return false;}return true;}int Sum(){int s=0;for(int i=0;i<12;++i)s+=b[a[i]];return s;}void out(){for(int i=11;i>=0;--i)printf("%d ",a[i]);printf("\n");}int main(){/*freopen("input.txt","r",stdin);*/int n,m,i,j,k,tmp,sum;while(~scanf("%d%d",&b[0],&b[1])){sum = 0;b[1]=-b[1];for(i=0;i<(1<<12);++i){c=0;j=i;while(c<12){a[c++]=j&1;j>>=1;}/*out();*/if(jugde()){sum=max(sum,Sum());}}if(sum!=0)printf("%d\n",sum);elseprintf("Deficit\n");}return 0;}