struts2 异常处理 404错误

struts.xml

<?xml version="1.0" encoding="UTF-8" ?>

<!DOCTYPE struts PUBLIC

"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"

"http://struts.apache.org/dtds/struts-2.0.dtd">

<struts>

<constant name="struts.i18n.encoding" value="UTF-8" />

<constant name="struts.custom.i18n.resources" value="guojihua" />

<constant name="struts.devMode" value="true" />

<!-- 所有的package都要必须继承struts-default，父类中继承，其就不需要继承 -->

<package name="exception" namespace="/exception" extends="struts-default">

<!-- 设置默认action，当找不到页面时会用此action -->

<default-action-ref name="notFind404"/>

<!-- 公共的跳转页面 -->

<global-results>

<result name="lang">/javaError.jsp</result>

<result name="sql">/sqlError.jsp</result>

</global-results>

<!-- 公共异常处理 -->

<global-exception-mappings>

<exception-mapping exception="java.lang.Exception" result="lang" />

<exception-mapping exception="java.sql.SQLException" result="sql" />

</global-exception-mappings>

<!-- 找不到页面后的跳转页面 -->

<action name="notFind404">

<result>/notFind404.jsp</result>

</action>

</package>

<!-- 继承exception 的package -->

<package name="lhy" namespace="/" extends="truts-default,exception" >

<action name="tiaozhuan" class="action.ExceptionAction" method="tiaozhuan">

<result name="tiaozhuan">/index.jsp</result>

</action>

<action name="javaError" class="action.ExceptionAction" method="javaError">

<result name="javaError">/index.jsp</result>

</action>

<action name="sqlError" class="action.ExceptionAction" method="sqlError">

<result name="sqlError">/index.jsp</result>

</action>

</package>

</struts>

ExceptionAction.java

package action;

import com.opensymphony.xwork2.ActionSupport;

public class ExceptionAction extends ActionSupport{

public String tiaozhuan()

{

return "tiaozhuan";

}

public String javaError()

{

int i=0;

int j=1;

int h=0;

h=j/i;//此处抛出异常,再struts中捕获

/* try{ //此处处理异常，在struts中无法捕获。

h=j/i;

}

catch(Exception e)

{

e.printStackTrace();

}*/

return "javaError";

}

public String sqlError()

{

return "sqlError";

}

}