sqlserver的树形查询

SQL Server没有ORACLE那样专门的树形查询语法，而这却是很多数据库模型中要用到的，比如主机结构，产品分类等。 我查询了很多资料没有一个满意的，基本有3中方案：

1. 简单的带with的递归查询，无法排序，更加无法显示体系架构

2 使用ROW_NUMBER()over功能，比较完美，但某些极端情况不能工作，复杂难懂

3 老外有存储过程来实现，很完美，但建立新的对象很不爽

我综合了各种方法，这是第4中方法，应该很完美了：

WITH tree

AS

(

SELECT ParentAssetID, AssetID,1 AS x2level,nodename,

CAST(nodename AS NVARCHAR(max)) x2name,

CAST(+AssetID AS NVARCHAR(max)) x2id

FROM dbo.Assets

WHERE ParentAssetID IS null

UNION ALL

SELECT c.ParentAssetID, c.AssetID, tree.x2level + 1,c.nodename,

CAST(REPLICATE('-', x2level * 4) + c.nodename AS NVARCHAR(max)) x2name,

tree.x2id +':|:'+ CAST(c.AssetID AS NVARCHAR(max)) x2id

FROM dbo.Assets c

INNER JOIN tree

ON c.ParentAssetID = tree.AssetID

)

SELECT x2name, AssetID, ParentAssetID FROM tree

ORDER BY x2id;

---President

------Vice President

---------CEO

---------CTO

------------Group Project Manager

---------------Project Manager 1

------------------Team Leader 1

---------------------Software Engineer 1

---------------------Software Engineer 2

------------------Test Lead 1

---------------------Tester 1

---------------------Tester 2

---------------Project Manager 2

------------------Team Leader 2

---------------------Software Engineer 3

---------------------Software Engineer 4

------------------Test Lead 2

---------------------Tester 3

---------------------Tester 4

---------------------Tester 5