使用json-lib 把javabean转换成json串

（1）. jar包

* 略

. （2）核心类

* JSONObject --> Map

> toString();

> JSONObject map = JSONObject.fromObject(person)：把对象转换成JSONObject对象

* JSONArray --> List

> toString()

> JSONArray jsonArray = JSONObject.fromObject(list)：把list转换成JSONArray对象

示例代码

（一）测试代码

package test.test.demo1;

import java.util.ArrayList;

import java.util.List;

import net.sf.json.JSONArray;

import net.sf.json.JSONObject;

import org.junit.Test;

/**

* 演示JSON-LIB小工具　

* @author cxf

*

*/

public class Demo1 {

/*

* 当map来用

*/

@Test

public void fun1() {

JSONObject map = new JSONObject();

map.put("name", "zhangSan");

map.put("age", 23);

map.put("sex", "male");

String s = map.toString();

System.out.println(s);

}

/*

* 当你已经有一个Person对象时，可以把Person转换成JSONObject对象

*/

@Test

public void fun2() {

Person p = new Person("liSi", 32, "female");

// 把对象转换成JSONObject类型

JSONObject map = JSONObject.fromObject(p);

System.out.println(map.toString());

}

/**

* JSONArray

*/

@Test

public void fun3() {

Person p1 = new Person("zhangSan", 23, "male");

Person p2 = new Person("liSi", 32, "female");

JSONArray list = new JSONArray();

list.add(p1);

list.add(p2);

System.out.println(list.toString());

}

/**

* 原来就有一个List，我们需要把List转换成JSONArray

*/

@Test

public void fun4() {

Person p1 = new Person("zhangSan", 23, "male");

Person p2 = new Person("liSi", 32, "female");

List<Person> list = new ArrayList<Person>();

list.add(p1);

list.add(p2);

System.out.println(JSONArray.fromObject(list).toString());

}

}

（二）person类

package cn.itcast.demo1;

public class Person {

private String name;

private int age;

private String sex;

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

public int getAge() {

return age;

}

public void setAge(int age) {

this.age = age;

}

public String getSex() {

return sex;

}

public void setSex(String sex) {

this.sex = sex;

}

public Person() {

super();

}

public Person(String name, int age, String sex) {

super();

this.name = name;

this.age = age;

this.sex = sex;

}

@Override

public String toString() {

return "Person [name=" + name + ", age=" + age + ", sex=" + sex + "]";

}

}