Oracle或者PostgreSQL的row_number over 排名语法
2015-09-16 18:03
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PostgreSQL 和Oracle 都提供了 row_number() over() 这样的语句来进行对应的字段排名, 很是方便。 MySQL却没有提供这样的语法。
这次我提供的表结构如下,
[sql] view
plaincopy
Table "ytt.t1"
Column | Type | Modifiers
--------+-----------------------+-----------
i_name | character varying(10) | not null
rank | integer | not null
我模拟了20条数据来做演示。
[sql] view
plaincopy
t_girl=# select * from t1 order by i_name;
i_name | rank
---------+------
Charlie | 12
Charlie | 12
Charlie | 13
Charlie | 10
Charlie | 11
Lily | 6
Lily | 7
Lily | 7
Lily | 6
Lily | 5
Lily | 7
Lily | 4
Lucy | 1
Lucy | 2
Lucy | 2
Ytt | 14
Ytt | 15
Ytt | 14
Ytt | 14
Ytt | 15
(20 rows)
在PostgreSQL下,我们来对这样的排名函数进行三种不同的执行方式1:
第一种,完整的带有排名字段以及排序。
[sql] view
plaincopy
t_girl=# select i_name,rank, row_number() over(partition by i_name order by rank desc) as rank_number from t1;
i_name | rank | rank_number
---------+------+-------------
Charlie | 13 | 1
Charlie | 12 | 2
Charlie | 12 | 3
Charlie | 11 | 4
Charlie | 10 | 5
Lily | 7 | 1
Lily | 7 | 2
Lily | 7 | 3
Lily | 6 | 4
Lily | 6 | 5
Lily | 5 | 6
Lily | 4 | 7
Lucy | 2 | 1
Lucy | 2 | 2
Lucy | 1 | 3
Ytt | 15 | 1
Ytt | 15 | 2
Ytt | 14 | 3
Ytt | 14 | 4
Ytt | 14 | 5
(20 rows)
第二种,带有完整的排名字段但是没有排序。
[sql] view
plaincopy
t_girl=# select i_name,rank, row_number() over(partition by i_name ) as rank_number from t1;
i_name | rank | rank_number
---------+------+-------------
Charlie | 12 | 1
Charlie | 12 | 2
Charlie | 13 | 3
Charlie | 10 | 4
Charlie | 11 | 5
Lily | 6 | 1
Lily | 7 | 2
Lily | 7 | 3
Lily | 6 | 4
Lily | 5 | 5
Lily | 7 | 6
Lily | 4 | 7
Lucy | 1 | 1
Lucy | 2 | 2
Lucy | 2 | 3
Ytt | 14 | 1
Ytt | 15 | 2
Ytt | 14 | 3
Ytt | 14 | 4
Ytt | 15 | 5
(20 rows)
第三种, 没有任何排名字段,也没有任何排序字段。
[sql] view
plaincopy
t_girl=# select i_name,rank, row_number() over() as rank_number from t1;
i_name | rank | rank_number
---------+------+-------------
Lily | 7 | 1
Lucy | 2 | 2
Ytt | 14 | 3
Ytt | 14 | 4
Charlie | 12 | 5
Charlie | 13 | 6
Lily | 7 | 7
Lily | 4 | 8
Ytt | 14 | 9
Lily | 6 | 10
Lucy | 1 | 11
Lily | 7 | 12
Ytt | 15 | 13
Lily | 6 | 14
Charlie | 11 | 15
Charlie | 12 | 16
Lucy | 2 | 17
Charlie | 10 | 18
Lily | 5 | 19
Ytt | 15 | 20
(20 rows)
这次我提供的表结构如下,
[sql] view
plaincopy
Table "ytt.t1"
Column | Type | Modifiers
--------+-----------------------+-----------
i_name | character varying(10) | not null
rank | integer | not null
我模拟了20条数据来做演示。
[sql] view
plaincopy
t_girl=# select * from t1 order by i_name;
i_name | rank
---------+------
Charlie | 12
Charlie | 12
Charlie | 13
Charlie | 10
Charlie | 11
Lily | 6
Lily | 7
Lily | 7
Lily | 6
Lily | 5
Lily | 7
Lily | 4
Lucy | 1
Lucy | 2
Lucy | 2
Ytt | 14
Ytt | 15
Ytt | 14
Ytt | 14
Ytt | 15
(20 rows)
在PostgreSQL下,我们来对这样的排名函数进行三种不同的执行方式1:
第一种,完整的带有排名字段以及排序。
[sql] view
plaincopy
t_girl=# select i_name,rank, row_number() over(partition by i_name order by rank desc) as rank_number from t1;
i_name | rank | rank_number
---------+------+-------------
Charlie | 13 | 1
Charlie | 12 | 2
Charlie | 12 | 3
Charlie | 11 | 4
Charlie | 10 | 5
Lily | 7 | 1
Lily | 7 | 2
Lily | 7 | 3
Lily | 6 | 4
Lily | 6 | 5
Lily | 5 | 6
Lily | 4 | 7
Lucy | 2 | 1
Lucy | 2 | 2
Lucy | 1 | 3
Ytt | 15 | 1
Ytt | 15 | 2
Ytt | 14 | 3
Ytt | 14 | 4
Ytt | 14 | 5
(20 rows)
第二种,带有完整的排名字段但是没有排序。
[sql] view
plaincopy
t_girl=# select i_name,rank, row_number() over(partition by i_name ) as rank_number from t1;
i_name | rank | rank_number
---------+------+-------------
Charlie | 12 | 1
Charlie | 12 | 2
Charlie | 13 | 3
Charlie | 10 | 4
Charlie | 11 | 5
Lily | 6 | 1
Lily | 7 | 2
Lily | 7 | 3
Lily | 6 | 4
Lily | 5 | 5
Lily | 7 | 6
Lily | 4 | 7
Lucy | 1 | 1
Lucy | 2 | 2
Lucy | 2 | 3
Ytt | 14 | 1
Ytt | 15 | 2
Ytt | 14 | 3
Ytt | 14 | 4
Ytt | 15 | 5
(20 rows)
第三种, 没有任何排名字段,也没有任何排序字段。
[sql] view
plaincopy
t_girl=# select i_name,rank, row_number() over() as rank_number from t1;
i_name | rank | rank_number
---------+------+-------------
Lily | 7 | 1
Lucy | 2 | 2
Ytt | 14 | 3
Ytt | 14 | 4
Charlie | 12 | 5
Charlie | 13 | 6
Lily | 7 | 7
Lily | 4 | 8
Ytt | 14 | 9
Lily | 6 | 10
Lucy | 1 | 11
Lily | 7 | 12
Ytt | 15 | 13
Lily | 6 | 14
Charlie | 11 | 15
Charlie | 12 | 16
Lucy | 2 | 17
Charlie | 10 | 18
Lily | 5 | 19
Ytt | 15 | 20
(20 rows)
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