mongodb AggregationOutput list.iterator() 无限循环的问题

在mongodb中将获取到的聚集进行遍历的时候进入无限循环，代码：

@Override
public Object getLogwayList() {
Iterable<DBObject> list= pageAnaDao.getLogwayList().results();
while(list.iterator().hasNext()){
DBObject result = list.iterator().next();
String id = result.get("_id").toString();
Iterable<DBObject> listCount = (Iterable<DBObject>) result.get("counts");
while(listCount.iterator().hasNext()){
DBObject resultOne = listCount.iterator().next();
}
}
}

下边这句代码始终为真：

list.iterator().hasNext()

而下边这句一直返回到第一个元素：

DBObject result = list.iterator().next();

所以导致的结果就是不断遍历第一个元素，进入无限循环。正确的方式：

@Override
public Object getLogwayList() {
Iterable<DBObject> list= pageAnaDao.getLogwayList().results();
Iterator<DBObject> iterator= list.iterator();
List<LogWay> results = new ArrayList<LogWay>();
while(iterator.hasNext()){
DBObject result = iterator.next();
String id = result.get("_id").toString();
Iterable<DBObject> listCount = (Iterable<DBObject>) result.get("counts");
Iterator<DBObject> iteratorCount= listCount.iterator();
while(iteratorCount.hasNext()){
DBObject resultOne = iteratorCount.next();
}
}

或者采用foreach()循环，进行:

for (DBObject obj : output.results()) {
String id = obj.get("_id");
int times = Integer.parseInt(obj.get("times").toString());
System.out.println("ID IS "+id+" time: "+times);
}