Java字符串找出4个字节长度的字符

不解释，直接上代码：

由于Iteye代码贴四个字节的ＵＴＦ－８字符出错，特能图的方式发布几个特殊字符：



Java代码


public class Byte4Check {

public static void main(String args[]) throws UnsupportedEncodingException {

String nickName = "12葫";

byte[] t = nickName.substring(0, 1).getBytes("UTF-8");

for (byte tt : t) {

System.out.println(tt);

}

System.out.println("====================");

byte[] t1 = nickName.getBytes("UTF-8");

for (int i = 0; i < t1.length;) {

byte tt = t1[i];

if (CharUtils.isAscii((char) tt)) {

byte[] ba = new byte[1];

ba[0] = tt;

i++;

String result = new String(ba);

System.out.println("1个字节的字符");

System.out.println("字符为：" + result);

}

if ((tt & 0xE0) == 0xC0) {

byte[] ba = new byte[2];

ba[0] = tt;

ba[1] = t1[i+1];

i++;

i++;

String result = new String(ba);

System.out.println("2个字节的字符");

System.out.println("字符为：" + result);

}

if ((tt & 0xF0) == 0xE0) {

byte[] ba = new byte[3];

ba[0] = tt;

ba[1] = t1[i+1];

ba[2] = t1[i+2];

i++;

i++;

i++;

String result = new String(ba);

System.out.println("3个字节的字符");

System.out.println("字符为：" + result);

}

if ((tt & 0xF8) == 0xF0) {

byte[] ba = new byte[4];

ba[0] = tt;

ba[1] = t1[i+1];

ba[2] = t1[i+2];

ba[3] = t1[i+3];

i++;

i++;

i++;

i++;

String result = new String(ba);

System.out.println("4个字节的字符");

System.out.println("字符为：" + result);

}

}

}

}

参考文献：
http://www.yunmx.com/archives/2011/138.htm http://zh.wikipedia.org/wiki/UTF-8