shell 获取 目录名 当前目录名

Four ways to extract the current directory name

By Sergio Gonzalez Duran on November 06, 2007 (9:00:00 AM)

When you're programming a shell script, you often only need the current directory name, not the whole path that the

pwd

command
returns. Here are four ways you can extract only the current directory.

Using basename

Using the

basename

command is the easiest and simplest way to extract the current directory:

basename /usr/local/bin
bin

However, it isn't useful in a shell script with changing directory variables. You can combine it with

pwd

inside
backticks to make it more dynamic:

cd /usr/local/bin
basename `pwd`
bin

Using parameter substitution with echo

The bash scripting language is full of nice tricks, including parameter substitution, which allows you to manipulate or expand variables. You can use parameter substitution with the

${var##pattern}

syntax,
which removes from

$var

the longest part of

$Pattern

that
matches the front end of

$var

. Take a look at an example:

cd /var/log/squid
echo ${PWD##*/}
squid

PWD

is the environment variable that holds the current path, and ## is the instruction that tells the script
to remove everything it finds up to */. In other words, it removes everything until the last /, leaving only the last string, which here is the current directory,

squid

.
You can learn more about parameter substitution and other ways to manipulate variables in the Advanced Bash-Scripting
Guide.

Using awk and rev

A more elaborate solution uses a combination of

awk

(a pattern-scanning utility) and

rev

(a
utility that reverses lines from a file or from stdin):

cd /usr/share/cups/data
pwd | rev | awk –F \/ '{print $1}' | rev
data

It's a lot easier to understand this kind of script step by step:

pwd
/usr/share/cups/data
pwd | rev
atad/supc/erahs/rsu/
pwd | rev | awk –F \/ '{print $1}'
atad
pwd | rev | awk –F \/ '{print $1}' | rev
data

The

-F

option indicates that you should separate by fields, where the field delimiter is /, and that you should
print field 1.

Using sed

Finally, you can parse

pwd

output in the stream editor

sed

using
an elaborate regular expression. This approach may be educational, but it's not practical:

cd /home/smith/music
pwd | sed 's,^\(.*/\)\?\([^/]*\),\2,'
music

For a better understanding of how this works, remove the escape character (\), which is required for special characters such as "(":

sed 's,^(.*/)?([^/]*),\2,'

s

substitutes one string for another. It looks for two patterns, which are indicated between the first comma
and the second comma. The first pattern (

^(.*/)?

) searches from the beginning of the line (^) until the last
occurrence that it finds of / (in the example, it matches

/home/smith/

). The second pattern (

([^/]*)

)
searches everything from the last pattern except the / character , which is indicated by

[^/]*

, where ^ at the
beginning of the square brackets means not. This results in both

/home/smith/

and

music

.
The second part of this regular expression is the substitution, indicated by \2. In sed, this is called a back reference. As its name implies, it goes back and recalls a previously used reference. There may be nine
of these, named \1, \2, \3, and so on. In the example, \2 refers to the second pattern found, which is

music

--
the result expected.

As you can see, Linux gives you many ways to find a directory name. Having many choices for the same chore is one of its strengths.

Sergio Gonzalez Duran is a Linux administrator, systems developer, and network security counselor who also teaches Linux courses and publishes the Spanish-oriented Linux and open source Web site linuxtotal.com.mx.