您的位置:首页 > Web前端 > Node.js

[leetcode]51 Delete Node in a Linked List

2015-09-06 10:05 513 查看
题目链接:https://leetcode.com/problems/delete-node-in-a-linked-list/

runtime:16ms

1、问题

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

2、分析

这是一道有技巧的题目,咋一看不能解,但是链表的内容是可以变得,将当前节点的内容换成下一个节点的内容,删除下一个节点,解决问题。

3、小结

换一个思路,豁然开朗~

4、实现

/**
* Definition for singly-linked list.
* struct ListNode {
*     int val;
*     ListNode *next;
*     ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
void deleteNode(ListNode* node) {
ListNode *p = node->next;
ListNode *q = p->next;
node->val = p->val;
node->next = q;
delete(p);
}
};


5、反思

内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: