您的位置:首页 > 编程语言 > C语言/C++

C语言复习 -- 结构体指针与自增运算符

2015-09-02 09:41 477 查看
测试代码:

#include <stdio.h>

#include <stdlib.h>

int main() {

struct student {

char *name;

int score;

};

struct student st = {"Brian", 97};

struct student *ptr = &st;

printf("ptr->name = %s\n", ptr->name);

printf("*ptr->name = %c\n", *ptr->name);

printf("*ptr->name++ = %c\n", *ptr->name++);

printf("*ptr->name = %c\n", *ptr->name);

printf("ptr->score = %d\n", ptr->score);

printf("ptr->score++ = %d\n", ptr->score++);

printf("ptr->score = %d\n", ptr->score);

return 0;

}

=== 运行结果:

ptr->name = Brian

*ptr->name = B

*ptr->name++ = B

*ptr->name = r

ptr->score = 97

ptr->score++ = 97

ptr->score = 98

=== 分析:

1. ptr->name,这个不说了。

2. *ptr->name,因为->的优先级高于*,所以相当于: *(ptr->name)。即指针首地址的那个字符。

3. *ptr->name++,由于*和++的优先级相同,而且结合性是由右至左,所以相当于: *((ptr->name)++),即获取首地址字符后,将name指针右移一位。(当前打印还是首地址的值)

4. *ptr->name,此处为验证上一步的指针位置。
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: