【leetcode】Delete Node in a Linked List

Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

思路： 开始的时候还没有读懂题意。实际上就，给一个节点，删除该节点。那么只要把下一节点的值和指针赋给这个节点即可。

/**
* Definition for singly-linked list.
* struct ListNode {
*     int val;
*     ListNode *next;
*     ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
void deleteNode(ListNode* node) {
if (node == NULL)
return;
else
{
node->val=node->next->val;
node->next=node->next->next;
}
}
};