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找出oracle没有创建索引的外键

2015-07-16 16:27 579 查看
外键列没有索引,容易导致enq: TM - contention等待事件,所以外键列必须创建索引。

(1)下面的sql语句可以定位出哪些外键约束没有创建索引。

SELECT table_name, constraint_name, 

         cname1 

      || NVL2 (cname2, ',' || cname2, NULL) 

      || NVL2 (cname3, ',' || cname3, NULL) 

      || NVL2 (cname4, ',' || cname4, NULL) 

      || NVL2 (cname5, ',' || cname5, NULL) 

      || NVL2 (cname6, ',' || cname6, NULL) 

      || NVL2 (cname7, ',' || cname7, NULL) 

       || NVL2 (cname8, ',' || cname8, NULL) COLUMNS 

  FROM (SELECT   b.table_name, b.constraint_name, 

                 MAX (DECODE (POSITION, 1, column_name, NULL)) cname1, 

                 MAX (DECODE (POSITION, 2, column_name, NULL)) cname2, 

                 MAX (DECODE (POSITION, 3, column_name, NULL)) cname3, 

                 MAX (DECODE (POSITION, 4, column_name, NULL)) cname4, 

                 MAX (DECODE (POSITION, 5, column_name, NULL)) cname5, 

                 MAX (DECODE (POSITION, 6, column_name, NULL)) cname6, 

                 MAX (DECODE (POSITION, 7, column_name, NULL)) cname7, 

                 MAX (DECODE (POSITION, 8, column_name, NULL)) cname8, 

                 COUNT (*) col_cnt 

            FROM (SELECT SUBSTR (table_name, 1, 30) table_name, 

                         SUBSTR (constraint_name, 1, 30) constraint_name, 

                         SUBSTR (column_name, 1, 30) column_name, POSITION 

                    FROM user_cons_columns) a, 

                 user_constraints b 

           WHERE a.constraint_name = b.constraint_name 

             AND b.constraint_type = 'R' 

        GROUP BY b.table_name, b.constraint_name) cons 

 WHERE col_cnt > 

          ALL (SELECT   COUNT (*) 

                   FROM user_ind_columns i 

                  WHERE i.table_name = cons.table_name 

                    AND i.column_name IN 

                           (cname1, 

                            cname2, 

                            cname3, 

                            cname4, 

                            cname5, 

                            cname6, 

                            cname7, 

                            cname8 

                           ) 

                    AND i.column_position <= cons.col_cnt 

               GROUP BY i.index_name) 



(2)批量给没有索引的外键列创建索引

select 'create index ind_fk_'||table_name||' on '||table_name||' ('||columns||') online nologging;' from (

SELECT table_name, constraint_name, 

         cname1 

      || NVL2 (cname2, ',' || cname2, NULL) 

      || NVL2 (cname3, ',' || cname3, NULL) 

      || NVL2 (cname4, ',' || cname4, NULL) 

      || NVL2 (cname5, ',' || cname5, NULL) 

      || NVL2 (cname6, ',' || cname6, NULL) 

      || NVL2 (cname7, ',' || cname7, NULL) 

       || NVL2 (cname8, ',' || cname8, NULL) COLUMNS 

  FROM (SELECT   b.table_name, b.constraint_name, 

                 MAX (DECODE (POSITION, 1, column_name, NULL)) cname1, 

                 MAX (DECODE (POSITION, 2, column_name, NULL)) cname2, 

                 MAX (DECODE (POSITION, 3, column_name, NULL)) cname3, 

                 MAX (DECODE (POSITION, 4, column_name, NULL)) cname4, 

                 MAX (DECODE (POSITION, 5, column_name, NULL)) cname5, 

                 MAX (DECODE (POSITION, 6, column_name, NULL)) cname6, 

                 MAX (DECODE (POSITION, 7, column_name, NULL)) cname7, 

                 MAX (DECODE (POSITION, 8, column_name, NULL)) cname8, 

                 COUNT (*) col_cnt 

            FROM (SELECT SUBSTR (table_name, 1, 30) table_name, 

                         SUBSTR (constraint_name, 1, 30) constraint_name, 

                         SUBSTR (column_name, 1, 30) column_name, POSITION 

                    FROM user_cons_columns) a, 

                 user_constraints b 

           WHERE a.constraint_name = b.constraint_name 

             AND b.constraint_type = 'R' 

        GROUP BY b.table_name, b.constraint_name) cons 

 WHERE col_cnt > 

          ALL (SELECT   COUNT (*) 

                   FROM user_ind_columns i 

                  WHERE i.table_name = cons.table_name 

                    AND i.column_name IN 

                           (cname1, 

                            cname2, 

                            cname3, 

                            cname4, 

                            cname5, 

                            cname6, 

                            cname7, 

                            cname8 

                           ) 

                    AND i.column_position <= cons.col_cnt 

               GROUP BY i.index_name) 

)

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