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【LeetCode 38_字符串_算术运算】Count and Say

2015-07-07 20:08 543 查看


string countAndSay(int n)
{
string res;
if (n <= 0)
return res;

res = "1";
while (n-- > 1) {
int len = res.size();
int i, j;
string resTmp;

for (i = 0; i < len; i = j) {
char ch = res[i];

for (j = i + 1; j < len; ++j) {
if (ch != res[j])
break;
}

resTmp = resTmp + (char)(j - i + '0') + ch;
}
res = resTmp;
}
return res;
}
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