LeetCode-Compare Version Numbers解题报告

原题链接https://leetcode.com/problems/compare-version-numbers/

Compare two version numbers version1 and
version2.

If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the

.

character.

The

.

character does not represent a decimal point and is used to separate number sequences.

For instance,

2.5

is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

字符串处理而已 没什么难度

class Solution {
public:
int compareVersion(string version1, string version2) {
int p1 = 0, p2 = 0, i1, i2;
while (p1 < version1.length() || p2 < version2.length())
{
i1 = sti(version1, p1);
i2 = sti(version2, p2);
if (i1 > i2)return 1;
else if (i1 < i2)return -1;
continue;
}
return 0;

}
int sti(string& s, int& pos)
{
int res = 0;
while (pos < s.length() && s[pos] != '.')
{
res = res * 10 + (s[pos] - '0');
pos++;
}
pos++;
return res;
}
};