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用c++实现单向链表的创建,插入和删除

2015-07-03 17:33 751 查看
用c++实现单向链表的创建,插入和删除

#include<iostream>


using namespace std;

typedef struct NODE
{
int data;
struct NODE * next;
}node;

node * creat();
void print (node *head);
int Insert (node * head,int pos,int num);
int Delete (node * head,int pos);//删除第pos个结点

void main()
{
cout<<"线性表啊的链式实现方式   5.16\n";
node * head;
head=creat();//以head为表头创建一个链表
print (head);
int pos,num;
cout<<"\ninput the position and number to be insert\n";
cin>>pos>>num;
Insert (head,pos,num);
print (head);
cout<<"\ninput the position  to be delete\n";
cin>>pos;
int e=Delete(head,pos);
print (head);

cout<<endl;
}

node * creat()
{
node*head=NULL;
node*end=NULL;
node*ps;
int num;
ps=new node;
ps->next=NULL;
head=ps;
end=ps;
cout<<"input  numbers  end  with 0:";
cin>>num;
while(num!=0)
{
ps=new node;
ps->data=num;
end->next=ps;
end=ps;
cin>>num;
}
end->next=NULL;
return head;
}

void print (node * head)
{
node * travel  =head->next;
while(travel!=NULL)
{
cout<<travel->data<<' ';
travel=travel->next;
}
}

int Insert (node * head,int pos,int num)
{
node * p=head;
int j=0;
while(p&&j<pos-1)//若p!=null,循环pos-1次到pos-1个结点,再将创建的新结点插入到第pos个位置。
{
p=p->next;
++j;
}
if(!p||j>pos-1)
return 0;
node * s=(node *)malloc(sizeof(node));//生成新结点
s->data=num;
s->next=p->next;
p->next=s;
return 0;

}
int Delete (node * head,int pos) //删除第pos个结点
{
node * p= head;
int j=0;
while(p->next&&j<pos-1)
{

p=p->next;
j++;
}
if(!(p->next)||j>pos-1)
return 0;
node * q=p->next;
p->next=q->next;
int e=q->data;
free(q);
return e;
}
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