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java.util.zip.DataFormatException: invalid distance too far back

2015-06-17 11:51 537 查看
解压 war/jar文件时出现以下错误:

java.util.zip.ZipException: invalid distance too far back

at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.readFromInflater(ZipArchiveInputStream.java:478)

at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.readDeflated(ZipArchiveInputStream.java:443)

at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.read(ZipArchiveInputStream.java:384)

at java.io.InputStream.read(Unknown Source)

at org.apache.commons.compress.utils.IOUtils.copy(IOUtils.java:75)

at org.apache.commons.compress.utils.IOUtils.copy(IOUtils.java:56)

at com.xunge.AESFileEncoder$1.run(AESFileEncoder.java:149)

at java.lang.Thread.run(Unknown Source)

Caused by: java.util.zip.DataFormatException: invalid distance too far back

at java.util.zip.Inflater.inflateBytes(Native Method)

at java.util.zip.Inflater.inflate(Unknown Source)

at org.apache.commons.compress.archivers.zip.ZipArchiveInputStream.readFromInflater(ZipArchiveInputStream.java:476)

… 7 more

相关代码:

PipedInputStream pin = new PipedInputStream();
                    PipedOutputStream pout = new PipedOutputStream(pin);
                    new Thread(new Runnable() {
                        public void run() {
                            try {
                                IOUtils.copy(ais, pout);

                                pout.close();
                            } catch (IOException e) {
                                // TODO Auto-generated catch block
                                e.printStackTrace();
                            }
                        }
                    }).start();

                    ArchiveInputStream inJar = new ArchiveStreamFactory()
                            .createArchiveInputStream(ArchiveStreamFactory.JAR,
                                    pin);


以上代码是没有问题,如果使用 pin 的代码和 pin 的声明代码中间隔了太多的代码就会产生此异常。具体没有做试验,也可能是有逻辑判断语句的原因。
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