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Oracle分析函数之first_value和last_value 分析函数详解

2015-01-04 10:14 531 查看
FIRST_VALUE 返回组中数据窗口的第一个值 FIRST_VALUE ( [scalar_expression )OVER ( [ partition_by_clause ] order_by_clause )
LAST_VALUE   返回组中数据窗口的最后一个值  LAST_VALUE ( [scalar_expression )OVER ( [ partition_by_clause order_by_clause )


ORACLE函数:LAST_VALUE,FIRST_VALUE的用法:

1、初始化原始数据:

create table test (id number(2), name varchar2(10), salary number(6,2));

insert into test values (1,'Tom',120);

insert into test values (2,'Ellen',240);

insert into test values (2,'Joe',80);

insert into test values (3,'Andy',300);

insert into test values (3,'Kary',500);

insert into test values (3,'Erick',1300);

insert into test values (3,'Hou',40);

insert into test values (3,'Mary',200);

insert into test values (3,'Secooler',800);

commit;

select * from test order by ID,name;

 ID NAME         SALARY

--- ---------- --------

  1 Tom          120.00

  2 Ellen        240.00

  2 Joe           80.00

  3 Andy         300.00

  3 Erick       1300.00

  3 Hou           40.00

  3 Kary         500.00

  3 Mary         200.00

  3 Secooler     800.00

2、LAST_VALUE分析函数的简单用法

(1)在TEST表中添加一列,标识每一个数据分区中薪水最高的人名。

select ID, name, salary, LAST_VALUE(name) OVER (partition by ID order by salary ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as highest_sal_name from test order by ID, name;

 ID NAME         SALARY HIGHEST_SAL_NAME

--- ---------- -------- ----------------

  1 Tom          120.00 Tom

  2 Ellen        240.00 Ellen

  2 Joe           80.00 Ellen

  3 Andy         300.00 Erick

  3 Erick       1300.00 Erick

  3 Hou           40.00 Erick

  3 Kary         500.00 Erick

  3 Mary         200.00 Erick

  3 Secooler     800.00 Erick

注意其中“ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING”的使用,若省略效果如下。

select ID, name, salary, LAST_VALUE(name) OVER (partition by ID order by salary) as highest_sal_name from test order by ID,name;

 ID NAME         SALARY HIGHEST_SAL_NAME

--- ---------- -------- ----------------

  1 Tom          120.00 Tom

  2 Ellen        240.00 Ellen

  2 Joe           80.00 Joe

  3 Andy         300.00 Andy

  3 Erick       1300.00 Erick

  3 Hou           40.00 Hou

  3 Kary         500.00 Kary

  3 Mary         200.00 Mary

  3 Secooler     800.00 Secooler

显然这不是我们想要的效果:(,这是为什么呢~~~?给您一次思考和回答的机会。

如果对UNBOUNDED PRECEDING和UNBOUNDED FOLLOWING不熟悉,请参考Oracle官方文档“windowing_clause”http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions001.htm#i97640。

在TEST表中添加一列,标识每一个数据分区中薪水最高的薪水值。

col highest_sal_name for 9999

select ID, name, salary, LAST_VALUE(SALARY) OVER (partition by ID order by salary ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as highest_sal_name from test order by ID, name;

 ID NAME         SALARY HIGHEST_SAL_NAME

--- ---------- -------- ----------------

  1 Tom          120.00              120

  2 Ellen        240.00              240

  2 Joe           80.00              240

  3 Andy         300.00             1300

  3 Erick       1300.00             1300

  3 Hou           40.00             1300

  3 Kary         500.00             1300

  3 Mary         200.00             1300

  3 Secooler     800.00             1300

3、与之相对应的是FIRST_VALUE函数

select ID, name, salary, FIRST_VALUE(name) OVER (partition by ID order by salary ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as highest_sal_name from test order by ID, name;

 ID NAME         SALARY HIGHEST_SAL_NAME

--- ---------- -------- ----------------

  1 Tom          120.00 Tom

  2 Ellen        240.00 Joe

  2 Joe           80.00 Joe

  3 Andy         300.00 Hou

  3 Erick       1300.00 Hou

  3 Hou           40.00 Hou

  3 Kary         500.00 Hou

  3 Mary         200.00 Hou

  3 Secooler     800.00 Hou

select ID, name, salary, FIRST_VALUE(SALARY) OVER (partition by ID order by salary ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as highest_sal_name from test order by ID, name;

 ID NAME         SALARY HIGHEST_SAL_NAME

--- ---------- -------- ----------------

  1 Tom          120.00              120

  2 Ellen        240.00               80

  2 Joe           80.00               80

  3 Andy         300.00               40

  3 Erick       1300.00               40

  3 Hou           40.00               40

  3 Kary         500.00               40

  3 Mary         200.00               40

  3 Secooler     800.00               40

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