sqlserver 身份证号简单校验,筛选
2014-11-23 12:34
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--校验18位身份证,返回校验后的身份证号 ALTER FUNCTION [dbo].[CheckID18] (@ID char(18)) RETURNS CHAR(18) AS BEGIN DECLARE @ID18 CHAR(18) DECLARE @S1 AS INTEGER DECLARE @S2 AS INTEGER DECLARE @S3 AS INTEGER DECLARE @S4 AS INTEGER DECLARE @S5 AS INTEGER DECLARE @S6 AS INTEGER DECLARE @S7 AS INTEGER DECLARE @S8 AS INTEGER DECLARE @S9 AS INTEGER DECLARE @S10 AS INTEGER DECLARE @S11 AS INTEGER DECLARE @S12 AS INTEGER DECLARE @S13 AS INTEGER DECLARE @S14 AS INTEGER DECLARE @S15 AS INTEGER DECLARE @S16 AS INTEGER DECLARE @S17 AS INTEGER DECLARE @S18 AS INTEGER SET @S1 = SUBSTRING(@ID,1,1) SET @S2 = SUBSTRING(@ID,2,1) SET @S3 = SUBSTRING(@ID,3,1) SET @S4 = SUBSTRING(@ID,4,1) SET @S5 = SUBSTRING(@ID,5,1) SET @S6 = SUBSTRING(@ID,6,1) SET @S7 = SUBSTRING(@ID,7,1) SET @S8 = SUBSTRING(@ID,8,1) SET @S9 = SUBSTRING(@ID,9,1) SET @S10 = SUBSTRING(@ID,10,1) SET @S11 = SUBSTRING(@ID,11,1) SET @S12 = SUBSTRING(@ID,12,1) SET @S13 = SUBSTRING(@ID,13,1) SET @S14 = SUBSTRING(@ID,14,1) SET @S15 = SUBSTRING(@ID,15,1) SET @S16 = SUBSTRING(@ID,16,1) SET @S17 = SUBSTRING(@ID,17,1) SET @S18 = ( (@S1*7) + (@S2*9) + (@S3*10) + (@S4*5) + (@S5*8) + (@S6*4) + (@S7*2) + (@S8*1) + (@S9*6) + (@S10*3) + (@S11*7) + (@S12*9) + (@S13*10) + (@S14*5) + (@S15*8) + (@S16*4) + (@S17*2) ) % 11 SET @ID18 = SUBSTRING(@ID,1,17) + CASE WHEN @S18 = 0 THEN '1' WHEN @S18 = 1 THEN '0' WHEN @S18 = 2 THEN 'X' WHEN @S18 = 3 THEN '9' WHEN @S18 = 4 THEN '8' WHEN @S18 = 5 THEN '7' WHEN @S18 = 6 THEN '6' WHEN @S18 = 7 THEN '5' WHEN @S18 = 8 THEN '4' WHEN @S18 = 9 THEN '3' WHEN @S18 = 10 THEN '2' END RETURN @ID18 END
查看身份证校验不对的
--select *,KSData.dbo.checkid18(sfzh) from [表] where sfzh<>KSData.dbo.checkid18(sfzh)
更新不对的
--update [表] set sfzh=KSData.dbo.checkid18(sfzh) where sfzh<>KSData.dbo.checkid18(sfzh)
删除年份错的
--delete from [表] where substring(sfzh,7,2)<>'19'
查出月日错的
--delete from [表] where substring(sfzh,11,2)>12 or substring(sfzh,13,2)>31
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