您的位置:首页 > 编程语言 > Java开发

HashSet vs. TreeSet vs. LinkedHashSet

2014-11-17 15:02 309 查看
A Set contains no duplicate elements. That is one of the major reasons to use a set. There are 3 commonly used implementations of Set: HashSet, TreeSet and LinkedHashSet. When and which to use is an important question. In brief, if you need a fast set, you
should use HashSet; if you need a sorted set, then TreeSet should be used; if you need a set that can be store the insertion order, LinkedHashSet should be used.

1. Set Interface

Set interface extends Collection interface. In a set, no duplicates are allowed. Every element in a set must be unique. You can simply add elements to a set, and duplicates will be removed automatically.



2. HashSet vs. TreeSet vs. LinkedHashSet

HashSet is Implemented using a hash table. Elements are not ordered. The add, remove, and containsmethods have constant time complexity O(1).

TreeSet is implemented using a tree structure(red-black tree in algorithm book). The elements in a set are sorted, but the add, remove, and contains methods has time complexity of O(log (n)). It offers several methods to deal with the ordered set like first(),
last(), headSet(), tailSet(), etc.

LinkedHashSet is between HashSet and TreeSet. It is implemented as a hash table with a linked list running through it, so it provides the order of insertion. The time complexity of basic me
4000
thods is O(1).

3. TreeSet Example

TreeSet<Integer> tree = new TreeSet<Integer>();
tree.add(12);
tree.add(63);
tree.add(34);
tree.add(45);
 
Iterator<Integer> iterator = tree.iterator();
System.out.print("Tree set data: ");
while (iterator.hasNext()) {
System.out.print(iterator.next() + " ");
}

Output is sorted as follows:
Tree set data: 12 34 45 63


Now let's define a Dog class as follows:

class Dog {
int size;
 
public Dog(int s) {
size = s;
}
 
public String toString() {
return size + "";
}
}

Let's add some dogs to TreeSet like the following:

import java.util.Iterator;
import java.util.TreeSet;
 
public class TestTreeSet {
public static void main(String[] args) {
TreeSet<Dog> dset = new TreeSet<Dog>();
dset.add(new Dog(2));
dset.add(new Dog(1));
dset.add(new Dog(3));
 
Iterator<Dog> iterator = dset.iterator();
 
while (iterator.hasNext()) {
System.out.print(iterator.next() + " ");
}
}
}

Compile ok, but run-time error occurs:
Exception in thread "main" java.lang.ClassCastException: collection.Dog cannot be cast to java.lang.Comparable
at java.util.TreeMap.put(Unknown Source)
at java.util.TreeSet.add(Unknown Source)
at collection.TestTreeSet.main(TestTreeSet.java:22)


Because TreeSet is sorted, the Dog object need to implement java.lang.Comparable's compareTo()method like the following:

class Dog implements Comparable<Dog>{
int size;
 
public Dog(int s) {
size = s;
}
 
public String toString() {
return size + "";
}
 
@Override
public int compareTo(Dog o) {
return size - o.size;
}
}

The output is:
1 2 3


4. HashSet Example

HashSet<Dog> dset = new HashSet<Dog>();
dset.add(new Dog(2));
dset.add(new Dog(1));
dset.add(new Dog(3));
dset.add(new Dog(5));
dset.add(new Dog(4));
Iterator<Dog> iterator = dset.iterator();
while (iterator.hasNext()) {
System.out.print(iterator.next() + " ");
}

Output:
5 3 2 1 4


Note the order is not certain.

5. LinkedHashSet Example

LinkedHashSet<Dog> dset = new LinkedHashSet<Dog>();
dset.add(new Dog(2));
dset.add(new Dog(1));
dset.add(new Dog(3));
dset.add(new Dog(5));
dset.add(new Dog(4));
Iterator<Dog> iterator = dset.iterator();
while (iterator.hasNext()) {
System.out.print(iterator.next() + " ");
}

The order of the output is certain and it is the insertion order:
2 1 3 5 4


6. Performance testing

The following method tests the performance of the three class on add() method.

public static void main(String[] args) {
 
Random r = new Random();
 
HashSet<Dog> hashSet = new HashSet<Dog>();
TreeSet<Dog> treeSet = new TreeSet<Dog>();
LinkedHashSet<Dog> linkedSet = new LinkedHashSet<Dog>();
 
// start time
long startTime = System.nanoTime();
 
for (int i = 0; i < 1000; i++) {
int x = r.nextInt(1000 - 10) + 10;
hashSet.add(new Dog(x));
}
// end time
long endTime = System.nanoTime();
long duration = endTime - startTime;
System.out.println("HashSet: " + duration);
 
// start time
startTime = System.nanoTime();
for (int i = 0; i < 1000; i++) {
int x = r.nextInt(1000 - 10) + 10;
treeSet.add(new Dog(x));
}
// end time
endTime = System.nanoTime();
duration = endTime - startTime;
System.out.println("TreeSet: " + duration);
 
// start time
startTime = System.nanoTime();
for (int i = 0; i < 1000; i++) {
int x = r.nextInt(1000 - 10) + 10;
linkedSet.add(new Dog(x));
}
// end time
endTime = System.nanoTime();
duration = endTime - startTime;
System.out.println("LinkedHashSet: " + duration);
 
}

From the output below, we can clearly wee that HashSet is the fastest one.
HashSet: 2244768
TreeSet: 3549314
LinkedHashSet: 2263320


* The test is not precise, but can reflect the basic idea that TreeSet is much slower because it is sorted.

内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  java