JBPM4.4 使用非zip方式发布流程 实现流程图加载

JBPM4.4 显示流程图片，需要携带流程图发布；这样大多数是采用打包zip方式来部署流程，太过繁琐；所以我采用如下方式发布流程

RepositoryService repositoryService=  processEngine.getRepositoryService();
NewDeployment deploy= repositoryService.createDeployment();
deploy.addResourceFromClasspath("newSite.jpdl.xml")
.addResourceFromClasspath("newSite.png");

action接收processInstanceId，（一般情况下processInstanceId与ExecutionId相同）得到流程图，并在当前activity上画框，来显示流程走到哪里。

public String showImage(){
ProcessInstance processInstance = executionService
.findProcessInstanceById(pid);

String processDefinitionId = processInstance.getProcessDefinitionId();
ProcessDefinition processDefinition = repositoryService
.createProcessDefinitionQuery().processDefinitionId(
processDefinitionId).uniqueResult();

Set<String> activityNames = processInstance.findActiveActivityNames();
BufferedImage image = null;

for (String activityName : activityNames) {
ActivityCoordinates ac = repositoryService.getActivityCoordinates(
processInstance.getProcessDefinitionId(), activityName);

InputStream is = repositoryService.getResourceAsStream(
processDefinition.getDeploymentId(), processDefinition
.getImageResourceName());

image = ImageIO.read(is);
Graphics g = image.getGraphics();
g.setColor(new Color(255, 0, 0));

g.drawRect(ac.getX(), ac.getY(), ac.getWidth(), ac.getHeight());
g.dispose();
}

ByteArrayOutputStream output = new ByteArrayOutputStream();
ImageIO.write(image, "PNG", output);
ByteArrayInputStream input = new ByteArrayInputStream(output
.toByteArray());
this.setInputStream(input);
return SUCCESS;
}

structs里面配置result为stream类型，class交给spring处理没有集成的可以修改成原有路径

<action name="processImage" class="processImageAction">
<result type="stream">
<param name="contentType">image/png</param>
<param name="inputName">inputStream</param>
</result>
</action>

jsp页面显示

<img src="processImage.action?pid=<s:property value='id'/>"/>