java中用try如果catch到异常，怎么把这个异常处理掉让程序继续运行

需要先将Scanner内的输入清楚，不然就重复读取了。简单调用Scanner 的next()方法就可以了





测试已通过

package zhidao;

import java.util.Scanner;

public class Retry {

private int myInt;

private Scanner myScanner = new Scanner(System.in);

public int getInt() {

try {

System.out.println("请输入法整数");

this.myInt = this.myScanner.nextInt();

} catch (Exception e) {

System.out.println("输入错误，请输入正确的数值!!!");

this.myScanner.next();

this.getInt();

}

return this.myInt;

}

public static void main(String[] args) {

Retry retry = new Retry();

System.out.println(retry.getInt());

}

}