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2014牡丹江网络预选赛F题(隐式图BFS暴搜)zoj3814

2014-09-11 00:37 459 查看
Sawtooth Puzzle

Time Limit: 10 Seconds Memory Limit: 65536 KB

Recently, you found an interesting game called Sawtooth Puzzle. This is a single-player game played on a grid with 3 x 3 cells. Each cell contains a part of an image. Besides,
each edge of a cell will be either smooth or saw-toothed. Two edge-adjacent cells are considered as meshed if their adjacent edges are both saw-toothed.
The game contains zero or more steps. At each step, the player can choose one cell, rotate it by 90 degrees clockwise. At the beginning of rotation, any cell which is going to rotate
will drive other cells to rotate together if they are meshed. Of course, the driven (passive) cell will rotate in the opposite direction against the driver (active) cell. The following image demonstrates the procedure of rotating the middle cell clockwise:



Given the initial image and target image of the puzzle, please find out the minimum number of steps needed to solve it.

Input

There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:
The input data consists of three parts. The first part represents the initial image of the puzzle. It contains 26 lines. Each line has 26 characters (excluding the line break '\n'). The
image is composed of 3 x 3 cells. Each cell is a monochrome image of 8 x 8 pixels ('#' for black, '.' for white). These cells are separated by space characters of 1 pixel width.
The second part represents the target image of the puzzle. It has the same format as which described above.
The last part contains 9 lines. Each line has 4 integers indicating the edge type (0 for smooth, 1 for saw-toothed) of a cell. The cells are listed in the order of top-left, top-middle,
top-right, middle-left, ... , till bottom-right. For each cell, the edge type are given in the order of left, top, right and bottom.
There is an empty line between any two adjacent parts (including of different cases).

Output

For each test case, output the minimum number of steps needed to solve the puzzle. If there is no solution, output -1 instead.

Sample Input

1
......#. ........ ........
......## ........ ........
.......# #....... ........
.......# ##...... ...##...
.......# ###..... .###....
.......# ####...# ####....
.......# ######## ###.....
.......# ######## ###.....

........ ######## ###.....
.......# ######## ##......
.....### ######## ##......
....#### ######## ###.....
..###### ######## ####....
######## ######## #####...
...##### ######## ######..
........ ######## #######.

........ ........ ..######
........ .....### ........
........ ######## ........
........ .####### ........
........ ...##### ........
........ .....### ........
........ .......# ........
........ ........ ........

......#. ........ ........
......## ........ ........
.......# #....... ........
.......# ##...... ...##...
.......# ###..... .###....
.......# ####...# ####....
.......# ######## ###.....
.......# ######## ###.....

........ ######## ###.....
.......# ######## ##......
.....### ######## ##......
....#### ######## ###.....
..###### ######## ####....
######## ######## #####...
...##### ######## ######..
........ ######## #######.

........ .######. ..######
........ .#####.. ........
........ .#####.. ........
........ ..###... ........
........ ..###... ........
........ ..##.... ........
........ ..##.... ........
........ ..#..... ........

0 1 0 1
0 0 1 1
1 0 0 1
0 0 1 1
1 1 1 0
1 0 1 1
1 1 1 1
0 0 1 0
0 1 1 0

Sample Output

6


题意:RT

思路:BFS暴搜

注意以下几点即可:

1.每次扩展状态的时候要对9个方块分别右旋

2.终点的状态可能有很多个,因为有的格子旋转以后的图案还是和之前一样

3.处理的时候注意一下细节即可(这个把我坑了好久,比如我在旋转第3个块的时候把它左边的块也旋转了,实际上它的左边是没有块的)
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