C#中List<T>对象的深度拷贝问题

List<T> oldList = new List<T>();
oldList.Add(..);
List<T> newList = new List<T>(oldList);

static class Extensions
{
public static IList<T> Clone<T>(this IList<T> listToClone) where T: ICloneable
{
return listToClone.Select(item => (T)item.Clone()).ToList();
}
//当然前题是List中的对象要实现ICloneable接口
}

public static T Clone<T>(T RealObject)

{
using (Stream objectStream = new MemoryStream())
{
//利用 System.Runtime.Serialization序列化与反序列化完成引用对象的复制
IFormatter formatter = new BinaryFormatter();
formatter.Serialize(objectStream, RealObject);
objectStream.Seek(0, SeekOrigin.Begin);
return (T)formatter.Deserialize(objectStream);
}
}

public static T Clone<T>(T RealObject)
{
using(Stream stream=new MemoryStream())
{
XmlSerializer serializer = new XmlSerializer(typeof(T));
serializer.Serialize(stream, RealObject);
stream.Seek(0, SeekOrigin.Begin);
return (T)serializer.Deserialize(stream);
}
}

测试如下:

using System;
using System.Collections.Generic;
using System.Collections ;
using System.Linq;
using System.Text;
using System.IO;
using System.Runtime.Serialization;
using System.Runtime.Serialization.Formatters.Binary;

namespace LINQ
{
[Serializable]
public class tt
{
private string name = "";

public string Name
{
get { return name; }
set { name = value; }
}
private string sex = "";

public string Sex
{
get { return sex; }
set { sex = value; }
}
}

class LINQTest
{
public static T Clone<T>(T RealObject)
{
using (Stream objectStream = new MemoryStream())
{
IFormatter formatter = new BinaryFormatter();
formatter.Serialize(objectStream, RealObject);
objectStream.Seek(0, SeekOrigin.Begin);
return (T)formatter.Deserialize(objectStream);
}
}

public static void Main()
{
List<tt> lsttt = new List<tt>();
tt tt1 = new tt();
tt1.Name = "a1";
tt1.Sex = "20";
lsttt.Add(tt1);
List<tt> l333 = new List<tt>();
l333.Add(Clone<tt>(lsttt[0]));
l333[0].Name = "333333333";
}
}
}

作者：orange1438
出处：http://www.cnblogs.com/orange1438/
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