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java中通过位运算实现多个状态的判断

2014-08-31 22:51 281 查看
通过 << | & ~ 位运算,实现同时拥有多个状态

通过 << 定义数据的状态

public interface LogConstants {
/**
* 消耗标记
*/
short COST_ASSET = 1 << 0;
short COST_GOLD = 1 << 1;
short COST_BINDGOLD = 1 << 2;
short COST_SOPH = 1 << 3;
short COST_STRSOUL = 1 << 4;
short COST_REFSOUL = 1 << 5;
short COST_SOULSTONE = 1 << 6;
short COST_AAMHID = 1 << 7;
short COST_REALM = 1 << 8;
}


通过 |= 加入多个状态

short mark = 0;
int costSoph = channel.getSoph();
if (costSoph > 0) {
mark |= LogConstants.COST_SOPH;
}

if (costGold > 0) {
mark |= LogConstants.COST_GOLD;
}


通过 (m & LogConstants.COST_ASSET) > 0 判断是否拥有该状态

通过 m = (short) (m & ~LogConstants.COST_ASSET);扣除该状态

public void addCostLog(LogEvent event, Player player, short mark, int... args) {short m = mark;
for (int i : args) {
if ((m & LogConstants.COST_ASSET) > 0) {
m = (short) (m & ~LogConstants.COST_ASSET);
cost.setAsset(i);
} else if ((m & LogConstants.COST_GOLD) > 0) {
m = (short) (m & ~LogConstants.COST_GOLD);
cost.setGold(i);
} else if ((m & LogConstants.COST_BINDGOLD) > 0) {
m = (short) (m & ~LogConstants.COST_BINDGOLD);
cost.setBindGold(i);
} else if ((m & LogConstants.COST_SOPH) > 0) {
m = (short) (m & ~LogConstants.COST_SOPH);
cost.setSoph(i);
} else if ((m & LogConstants.COST_STRSOUL) > 0) {
m = (short) (m & ~LogConstants.COST_STRSOUL);
cost.setStrSoul(i);
} else if ((m & LogConstants.COST_REFSOUL) > 0) {
m = (short) (m & ~LogConstants.COST_REFSOUL);
cost.setRefSoul(i);
} else if ((m & LogConstants.COST_SOULSTONE) > 0) {
m = (short) (m & ~LogConstants.COST_SOULSTONE);
cost.setSoulStone(i);
} else if ((m & LogConstants.COST_AAMHID) > 0) {
m = (short) (m & ~LogConstants.COST_AAMHID);
cost.setAamhid(i);
} else if ((m & LogConstants.COST_REALM) > 0) {
m = (short) (m & ~LogConstants.COST_REALM);
cost.setRealm(i);
}
}
}
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