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UVA 题目11292 Dragon of Loowater

2014-08-21 14:46 281 查看


Problem C: The Dragon of Loowater

Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.

The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack
one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance.

One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights
to slay the dragon and save the kingdom.

The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of
the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height."

Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As
one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!


Input Specification:

The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines
each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres.

The last test case is followed by a line containing:
0 0


Output Specification:

For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line:
Loowater is doomed!


Sample Input:

2 3
5
4
7
8
4
2 1
5
5
10
0 0


Output for Sample Input:

11
Loowater is doomed!

思路:

就是简单的一个排序,排序之后进行遍历就好找到能够砍头的勇士即可,最后比较是否是有砍掉所有头的勇士,有的话输出总花费,没有的话输出制定字符即可。

没想到就是这个简单题,因为我们的多次提交不对,我们换用原代码,竟被冤枉抄袭,首先声明,我们没有抄袭,我们之前自己写的代码,总共提交了6次,都是judge error,最后是为了判断系统的判断是否出错,所以提交的源代码,之前写的代码,我们可以保证正确。其次,有不少实际上抄袭的队伍,竟然没有人来检举,实属不公平。算了抱怨就此结束。代码如下:

#include<stdio.h>
#include<algorithm>
using namespace std;
int a[20010],b[20010];
int main()
{
	int n,m;
	while(~scanf("%d%d",&n,&m),n+m)
	{
		int cost=0,i,j;
		for(i=0;i<n;i++)
		scanf("%d",&a[i]);
		for(j=0;j<m;j++)
		scanf("%d",&b[j]);
		sort(a,a+n);
		sort(b,b+m);
		int t=0;
		for(i=0;i<m;i++)
		{
			if(b[i]>=a[t])
			{
				cost+=b[i];
				++t;
				if(t==n)
				break;
			}
		}
		if(t<n)
		printf("Loowater is doomed!\n");
		else
		printf("%d\n",cost);
	}
	return 0;
}




Ondřej Lhoták
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