用PYTHON实现将电脑里的所有文件按大小排序，便于清理

import os,os.path
import glob

SUFFIXES = ['KB', 'MB', 'GB', 'TB', 'PB', 'EB', 'ZB', 'YB']

def approximate_size(size):
'''Convert a file size to human-readable form.

Keyword arguments:
size -- file size in bytes

Returns: string

'''
if size < 0:
raise ValueError('number must be non-negative')

multiple = 1024.0
for suffix in SUFFIXES:
size /= multiple
if size < multiple:
return '{0:.1f} {1}'.format(size, suffix)

rootDir = raw_input('Please input root dir:')
count = 0
fileDict = {}
sortfileDict = {}
for parent, dirnames, filenames in os.walk(rootDir):
#print('Folder: %s' % dirName)
for filename in filenames:
name = os.path.join(parent,filename)
try:
filesize = os.path.getsize(name)
except (OSError):
filesize = 0
fileDict[name] = filesize
count += 1
print count

sortfileDict = sorted(fileDict.iteritems(), key=lambda fileDict:fileDict[1], reverse = True)

fList = open('filelist.txt','w')
for i in range(len(sortfileDict)):
#print sortfileDict[i][0], "\t", sortfileDict[i][1]
fileList = "{0} \t {1} \n".format(sortfileDict[i][0], approximate_size(sortfileDict[i][1]))
fList.write(fileList)

fList.close()

print 'DONE'