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C语言中给main函数传递参数!

2014-04-14 16:54 393 查看
相信大家用C语言定义main函数时,大多数人的写法都是int main(void)。其实main函数是可以向其传递参数的,给个实例:

//给main函数传参实例:

#include <stdio.h>

#include <string.h>

//int main(int argc, char *argv[])

int main(int argc, char **argv)

{

char *array[3] = {"./main", "hello", "world"};

if (argc < 2)

{

printf("error!\n");

printf("./main str\n");



return -1;

}

printf("The first string of your command is:%s\n", argv[0]);

printf("The second string of your command is:%s\n", argv[1]);

printf("The third string of your command is:%s\n", argv[2]);



if (!strcmp(argv[0], array[0]))

{

printf("The first command execute successfully!\n");

}

if (!strcmp(argv[1], array[1]))

{

printf("The second command execute successfully!\n");

}

if (!strcmp(argv[2], array[2]))

{

printf("The third command execute successfully!\n");

}

return 0;

}

输出结果:

(1)若输入命令为:./main

则输出结果为:

error!

The command is:./main

(2)若输入命令为:./main hello world

则输出结果为:

The first string of your command is:./main

The second string of your command is:hello

The third string of your command is:world

The first command execute successfully!

The second command execute successfully!

The third command execute successfully!

大家可以利用这个程序模型干很多事呢!
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