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myeclipse通过数据表生成jpa或hibernate实体

2014-03-11 09:26 435 查看
就是说,如果你已经有了数据库表,那么你又不想手工书写jpa或hibernate实体(要谁都不想,还要自己写那么一大堆的注解),myeclipse能够帮助你自动生成。

1、首先你需要创建一个jpa项目:

如图在普通项目上点右键添加



2、打开生成工作环境



3、创建数据库连接

因为,myeclipse也要连接数据库获取表结构



4、填写连接信息



5、打开表列表,选择导出模式



6、保存导出实体工程选择

(这一步需要第1步的操作,否则,没有可选工程)



现在就生成了entity,如:

[java] view
plaincopy

package com.partner4java.entity;

import javax.persistence.Column;

import javax.persistence.Entity;

import javax.persistence.GeneratedValue;

import static javax.persistence.GenerationType.IDENTITY;

import javax.persistence.Id;

import javax.persistence.Table;

/**

* User entity. @author MyEclipse Persistence Tools

*/

@Entity

@Table(name = "user", catalog = "hello_world")

public class User implements java.io.Serializable {

// Fields

private Integer id;

private String username;

private String password;

private String address;

// Constructors

/** default constructor */

public User() {

}

/** minimal constructor */

public User(String username, String password) {

this.username = username;

this.password = password;

}

/** full constructor */

public User(String username, String password, String address) {

this.username = username;

this.password = password;

this.address = address;

}

// Property accessors

@Id

@GeneratedValue(strategy = IDENTITY)

@Column(name = "id", unique = true, nullable = false)

public Integer getId() {

return this.id;

}

public void setId(Integer id) {

this.id = id;

}

@Column(name = "username", nullable = false, length = 20)

public String getUsername() {

return this.username;

}

public void setUsername(String username) {

this.username = username;

}

@Column(name = "password", nullable = false, length = 20)

public String getPassword() {

return this.password;

}

public void setPassword(String password) {

this.password = password;

}

@Column(name = "address", length = 20)

public String getAddress() {

return this.address;

}

public void setAddress(String address) {

this.address = address;

}

}
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