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用PHP发送HTTP POST 请求,获得返回结果。(转)

2014-02-21 16:09 585 查看
<?php

$srv_ip = '192.168.10.188';//你的目标服务地址或频道.
$srv_port = 80;
$url = '/demo/test_query_string.php'; //接收你post的URL具体地址
$fp = '';
$resp_str = '';
$errno = 0;
$errstr = '';
$timeout = 10;
$post_str = "username=demo&str=aaaa";//要提交的内容.

//echo $url_str;
if ($srv_ip == '' || $dest_url == ''){
echo('ip or dest url empty<br>');
}
//echo($srv_ip);
$fp = fsockopen($srv_ip,$srv_port,$errno,$errstr,$timeout);
if (!$fp){
echo('fp fail');
}
$content_length = strlen($post_str);
$post_header = "POST $url HTTP/1.1\r\n";
$post_header .= "Content-Type: application/x-www-form-urlencoded\r\n";
$post_header .= "User-Agent: MSIE\r\n";
$post_header .= "Host: ".$srv_ip."\r\n";
$post_header .= "Content-Length: ".$content_length."\r\n";
$post_header .= "Connection: close\r\n\r\n";
$post_header .= $post_str."\r\n\r\n";
fwrite($fp,$post_header);
while(!feof($fp)){
$resp_str .= fgets($fp,512);//返回值放入$resp_str
}
fclose($fp);
echo($resp_str);//处理返回值.
//unset ($resp_str);
?>
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标签:  PHP