您的位置：首页 > 运维架构 > Shell

shell $'somestring'

2013-12-01 11:10 246 查看
IFS默认支持 空格 tab 换行符

改变 IFS

IFS=$'\n'

IFS='\n'

IFS=\n

Normally 
bash
doesn't interpret escape sequences in string literals. So if you write 
\n
or 
"\n"
or
'\n'
, that's not a linebreak - it's the letter 
n
(in the first case) or a backslash followed by the letter 
n
(in the other two cases).

$'somestring'
is a syntax for string literals with escape sequences. So unlike 
'\n'
, 
$'\n'
actually is a linebreak.
内容来自用户分享和网络整理，不保证内容的准确性，如有侵权内容，可联系管理员处理 点击这里给我发消息
标签： 
相关文章推荐
新的分享
章节导航