【总结】java regex 正则表达式 提取数字和去除数字,过滤数字,提取价格

@Test
public void test33() {
String phoneString = "哈哈,13888889999";
// 提取数字
// 1
Pattern pattern = Pattern.compile("[^0-9]");
Matcher matcher = pattern.matcher(phoneString);
String all = matcher.replaceAll("");
System.out.println("phone:" + all);
// 2
Pattern.compile("[^0-9]").matcher(phoneString).replaceAll("");
}

@Test
public void test() {
// 提取张三 去除数字
String r_name3 = "张三 13599998888 000000";
Pattern pattern = Pattern.compile("[\\d]");
Matcher matcher = pattern.matcher(r_name3);
System.out.println(matcher.replaceAll("").trim());
}

String abc = "价格：0.00元";
Pattern compile = Pattern.compile("\\d+\\.\\d+");
Matcher matcher = compile.matcher(abc);
matcher.find();
String string = matcher.group();//提取匹配到的结果
System.out.println(string);//0.00

String abc = "手机：1319999999";
System.out.println(abc.replaceAll("\\D", ""));//1319999999

package com.infomorrow.parser_datasource;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

import org.junit.Test;

public class test_money {
@Test
public void test(){
//0
//0.1
//24.13
String moneyString="1";
Double extract_cost = extract_cost_dot(moneyString);
System.out.println("extract_cost:"+extract_cost);
}
/**
* 提取金额,规则为只提取数字和点号,必须有点号
* 格式可以为0.0或者，11
* @param cost
* @return
*/
public   Double extract_cost_dot(String cost) {
Pattern compile = Pattern.compile("(\\d+\\.\\d+)|(\\d+)");
Matcher matcher = compile.matcher(cost);
matcher.find();
return Double.valueOf(matcher.group());
}
}