进程中调用CreateMutex 分类： VC++ 2013-10-09 09:13 599人阅读 评论(0) 收藏

// TestStorage.cpp : 定义控制台应用程序的入口点。

//

#include "stdafx.h"

#include <Windows.h>

#include <process.h>

//#define MUTEX_DBG

UINT WINAPI Thread1(LPVOID para)

{

#ifdef MUTEX_DBG

HANDLE* phMutex = (HANDLE*)para;

WaitForSingleObject(*phMutex,INFINITE);

#endif

printf("Enter Thread1/n");

printf("I'm sleeping……/n");

Sleep(1000);

printf("Leave Thread1/n");

#ifdef MUTEX_DBG

ReleaseMutex(*phMutex);

#endif

return 0;

}

UINT WINAPI Thread2(LPVOID para)

{

#ifdef MUTEX_DBG

HANDLE* phMutex = (HANDLE*)para;

WaitForSingleObject(*phMutex,INFINITE);

#endif

printf("Enter Thread2/n");

printf("I'm sleeping……/n");

Sleep(1000);

printf("Leave Thread2/n");

#ifdef MUTEX_DBG

ReleaseMutex(*phMutex);

#endif

return 0;

}

int _tmain(int argc, _TCHAR* argv[])

{

HANDLE hMutex = NULL;

#ifdef MUTEX_DBG

hMutex = CreateMutex(NULL,FALSE,NULL);

#endif

HANDLE hThread1 = (HANDLE)::_beginthreadex(NULL,0,Thread1,&hMutex,0,NULL);

HANDLE hThread2 = (HANDLE)::_beginthreadex(NULL,0,Thread2,&hMutex,0,NULL);

Sleep(4000);

if(hThread1)

CloseHandle( hThread1 );

if(hThread2)

CloseHandle( hThread2 );

return 0;

}