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文章摘要java实现

2013-09-25 09:10 309 查看
实现自动摘要思路:

1.利用es-ik进行文章分词。

2.统计出词频最多的前100个分词(根据情况自己设定)。

3.对文章按句子进行分组。遍历词频最多的前100个分词,查找该分词所在的句子。然后进行统计输出(可以设定返回的句子数)。

关于其算法参考了Classifier4J的java实现。

参考文章:TF-IDF与余弦相似性的应用(三):自动摘要

相关代码实现已经github上。具体地址为:https://github.com/awnuxkjy/recommend-system

package com.xq.algorithm;

import java.io.IOException;
import java.io.Reader;
import java.io.StringReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.Iterator;
import java.util.LinkedHashMap;
import java.util.LinkedHashSet;
import java.util.List;
import java.util.Map;
import java.util.Set;

import org.wltea.analyzer.core.IKSegmenter;
import org.wltea.analyzer.core.Lexeme;

/**
*
* <p>Title:</p>
* <p>Description: SimpleSummariser
* </p>
* @createDate:2013-8-26
* @author xq
* @version 1.0
*/
public class SimpleSummariserAlgorithm {

/**
*
* @Title: summarise
* @Description: 文章摘要实现
* @param @param input
* @param @param numSentences
* @param @return
* @return String
* @throws
*/
public static String summarise(String input, int numSentences) {
// get the frequency of each word in the input
Map<String,Integer> wordFrequencies = segStr(input);

// now create a set of the X most frequent words
Set<String> mostFrequentWords = getMostFrequentWords(100, wordFrequencies).keySet();

// break the input up into sentences
// workingSentences is used for the analysis, but
// actualSentences is used in the results so that the
// capitalisation will be correct.
String[] workingSentences = getSentences(input.toLowerCase());
String[] actualSentences = getSentences(input);

// iterate over the most frequent words, and add the first sentence
// that includes each word to the result
Set<String> outputSentences = new LinkedHashSet<String>();
Iterator<String> it = mostFrequentWords.iterator();
while (it.hasNext()) {
String word = (String) it.next();
for (int i = 0; i < workingSentences.length; i++) {
if (workingSentences[i].indexOf(word) >= 0) {
outputSentences.add(actualSentences[i]);
break;
}
if (outputSentences.size() >= numSentences) {
break;
}
}
if (outputSentences.size() >= numSentences) {
break;
}

}

List<String> reorderedOutputSentences = reorderSentences(outputSentences, input);

StringBuffer result = new StringBuffer("");
it = reorderedOutputSentences.iterator();
while (it.hasNext()) {
String sentence = (String) it.next();
result.append(sentence);
result.append("."); // This isn't always correct - perhaps it should be whatever symbol the sentence finished with
if (it.hasNext()) {
result.append(" ");
}
}

return result.toString();
}

/**
*
* @Title: reorderSentences
* @Description: 将句子按顺序输出
* @param @param outputSentences
* @param @param input
* @param @return
* @return List<String>
* @throws
*/
private static List<String> reorderSentences(Set<String> outputSentences, final String input) {
// reorder the sentences to the order they were in the
// original text
ArrayList<String> result = new ArrayList<String>(outputSentences);

Collections.sort(result, new Comparator<String>() {
public int compare(String arg0, String arg1) {
String sentence1 = (String) arg0;
String sentence2 = (String) arg1;

int indexOfSentence1 = input.indexOf(sentence1.trim());
int indexOfSentence2 = input.indexOf(sentence2.trim());
int result = indexOfSentence1 - indexOfSentence2;

return result;
}

});
return result;
}

/**
*
* @Title: getMostFrequentWords
* @Description: 对分词进行按数量排序,取出前num个
* @param @param num
* @param @param words
* @param @return
* @return Map<String,Integer>
* @throws
*/
public static Map<String, Integer> getMostFrequentWords(int num,Map<String, Integer> words){

Map<String, Integer> keywords = new LinkedHashMap<String, Integer>();
int count=0;
// 词频统计
List<Map.Entry<String, Integer>> info = new ArrayList<Map.Entry<String, Integer>>(words.entrySet());
Collections.sort(info, new Comparator<Map.Entry<String, Integer>>() {
public int compare(Map.Entry<String, Integer> obj1, Map.Entry<String, Integer> obj2) {
return obj2.getValue() - obj1.getValue();
}
});

// 高频词输出
for (int j = 0; j < info.size(); j++) {
// 词-->频
if(info.get(j).getKey().length()>1){
if(num>count){
keywords.put(info.get(j).getKey(), info.get(j).getValue());
count++;
}else{
break;
}
}
}
return keywords;
}

/**
*
* @Title: segStr
* @Description: 返回LinkedHashMap的分词
* @param @param content
* @param @return
* @return Map<String,Integer>
* @throws
*/
public static Map<String, Integer> segStr(String content){
// 分词
Reader input = new StringReader(content);
// 智能分词关闭(对分词的精度影响很大)
IKSegmenter iks = new IKSegmenter(input, true);
Lexeme lexeme = null;
Map<String, Integer> words = new LinkedHashMap<String, Integer>();
try {
while ((lexeme = iks.next()) != null) {
if (words.containsKey(lexeme.getLexemeText())) {
words.put(lexeme.getLexemeText(), words.get(lexeme.getLexemeText()) + 1);
} else {
words.put(lexeme.getLexemeText(), 1);
}
}
}catch(IOException e) {
e.printStackTrace();
}
return words;
}

/**
*
* @Title: getSentences
* @Description: 把段落按. ! ?分隔成句组
* @param @param input
* @param @return
* @return String[]
* @throws
*/
public static String[] getSentences(String input) {
if (input == null) {
return new String[0];
} else {
// split on a ".", a "!", a "?" followed by a space or EOL
//"(\\.|!|\\?)+(\\s|\\z)"
return input.split("(\\.|!|\\?)");
}

}

public static void main(String[] args){
String s="被告人:对? 关于王立军,有几个基本事实.首先,1月28日我是初次听到此事.并不相信谷开来会杀人.我跟11·15杀人案无关.我不是谷开来11·15杀人罪的共犯.这个大家都认可.实际上谷开来3月14日她在北京被抓走!" +
"在这之前她一直非常确切地跟我说她没杀人,是王立军诬陷她.我在1月28日和次听到这个事时我不相信她会杀人." +
"第二个事实,免王立军的局长.是多个因素.一个,我确实认为他诬陷谷开来.但我并不是想掩盖11·15,我是觉得他人品不好." +
"因为谷开来和他是如胶似漆,谷开来对他是言听计从,那王立军也通过与谷开来的交往中打入了我的家庭." +
"那现在发生这么严重的事.作为一个起码的人,要讲人格的话,你干吗不找谷开来商量,而跑我这里来说这些话?" +
"第二个免他的原因,是他想要挟我.他多次谈他身体不好,打黑压力大,得罪了人." +
"其实这是在表功.第三,徐某某给我反映了他有五六条问题.有记录.实际上免他是有这些原因的,绝不只是一个谷开来的原因.这是多因一果.";
System.out.println(summarise(s, 3));
}
}
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