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JQuery、JSON、Ajax在Servlet中的应用

2013-09-06 23:40 821 查看

准备条件：

1、在Java中正确得到JSONObject，需要导入JSON的JAVA支持包“json-lib-2.3-jdk15.jar”，同时需导入 JSON依赖包“commons-logging-1.0.4.jar”，“commons-lang.jar”，“commons- collections.jar”，“commons-beanutils.jar”，“ezmorph-1.0.4.jar”；

2、由于在客户端脚本中要用到JQuery与JSON，需引入"JQuery.js"与"json2.js"。

JAVA 代码如下：

package example;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.PrintWriter;

import javax.servlet.ServletException;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

import net.sf.json.JSONObject;

public class JasonServlet extends HttpServlet {

/**

* Constructor of the object.

*/

public JasonServlet() {<
4000
br />
   super();

}

public void destroy() {

   super.destroy(); // Just puts "destroy" string in log

   // Put your code here

}

public void doGet(HttpServletRequest request, HttpServletResponse response)

    throws ServletException, IOException {

   doPost(request, response);

}

public void doPost(HttpServletRequest request, HttpServletResponse response) {

   try {

    String userStr = readJSONString(request);//得到requestContext

    JSONObject jsonObj = JSONObject.fromObject(userStr);//转换成JSONObject

    System.out.println(jsonObj.getInt("userId"));//得到JSONObject的userId值

    System.out.println(jsonObj.getString("name"));

    JSONObject resultJSON = new JSONObject();//构建一个JSONObject

    resultJSON.accumulate("errNum", 1);

    resultJSON.accumulate("errInfo", "成功");

    response.setContentType("application/x-json");//需要设置ContentType 为"application/x-json"

    PrintWriter out = response.getWriter();

    out.println(resultJSON.toString());//向客户端输出JSONObject字符串

    out.flush();

    out.close();

   } catch (Exception e) {

    e.printStackTrace();

   }

}

/**

* Initialization of the servlet. <br>

*

* @throws ServletException

*             if an error occure

*/

public void init() throws ServletException {

   // Put your code here

}

public String readJSONString(HttpServletRequest request){

   StringBuffer json = new StringBuffer();

   String line = null;

   try {

   BufferedReader reader = request.getReader();

   while((line = reader.readLine()) != null) {

   json.append(line);

   }

   }

   catch(Exception e) {

   System.out.println(e.toString());

   }

   return json.toString();

   }

}

JSP代码：

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>

<%

String path = request.getContextPath();

String basePath = request.getScheme() + "://"

    + request.getServerName() + ":" + request.getServerPort()

    + path + "/";

%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<html>

<head>

   <title>My JSP 'JasonTest.jsp' starting page</title>

   <meta http-equiv="pragma" content="no-cache">

   <meta http-equiv="cache-control" content="no-cache">

   <meta http-equiv="expires" content="0">

   <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">

   <meta http-equiv="description" content="This is my page">

   

   <script type="text/javascript" src="js/jquery.min.js"></script>

   <script type="text/javascript" src="js/json2.js"></script>

</head>

<body>

   <script type="text/javascript">

function User(userId, name) {

this.userId = userId;

this.name = name;

}

function requestServlet()

{

var urlStr="http://192.168.1.118:8080/AjaxTest/servlet/JasonServlet";

var user = JSON.stringify(new User(101,"阿猫"));

//调用JQuery提供的Ajax方法

    $.ajax({

    type:"POST",

   url:urlStr,

   data:user,

   dataType: "jason",//此处要设置成jason

   success: callback});//回调函数

   }

function callback(jasonObj)

{

var str = jasonObj;

   var obj = JSON.parse(str);//调用Json2.js中提供的JSON解析器来解析成JSONObject

    alert(obj.errNum);

   }

requestServlet();

</script>

</body>
</html>

转载自：http://xinkong1010.iteye.com/blog/635743

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标签： servlet jquery json

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