Oracle bug 使用max或min函数into到一个char类型报字符缓冲区太小的错误
2013-06-28 23:01
627 查看
这个BUG出现会报错如下:
selectto_char(max(RENEWAL_DATE)) intoM_YEAR_MONTH fromt_renewal_schedule;
ORA-06502: PL/SQL:数字或值错误: 字符串缓冲区太小
这个时候有3个方法可以解决
1、setting initialisation parameter BLANK_TRIMMING=TRUE
2、declare PL/SQL CHAR and VARCHAR2 variable used in the INTO clause of SELECT statement as 4,000 bytes.
3、Use CAST SQL function to constraint the size to that of the variable size like
SELECT CAST(MIN('Y') AS CHAR(1)) INTO C FROM DUAL;
CAST是强制转换函数。
参数BLANK_TRIMMING设置为TRUE的时候可以解决我们的BUG问题,同时这个参数设置为TRUE会在进行变量的赋值的时候忽略末尾的空格,同时这个参数必须关闭数据库进行更改。所以请评估下,是否可行。
试验如下:
SQL> CREATE TABLE abc (
2 cont_no char(8),
3 plan_id char(7));
Table created
SQL> INSERT INTO abc VALUES ('123456 ', '7654321'); ---(这里空格有2位)
1 row inserted
SQL> commit;
SQL> DECLARE
2 c_Plan_ID char(6);
3 BEGIN
4 SELECT cont_no INTO c_Plan_ID from abc;
5 dbms_output.put_line(c_Plan_ID);
6 END;
7 /
DECLARE
c_Plan_ID char(6);
BEGIN
SELECT cont_no INTO c_Plan_ID from abc;
dbms_output.put_line(c_Plan_ID);
END;
ORA-06502: PL/SQL:数字或值错误: 字符串缓冲区太小
ORA-06512:在line 5
然后我们修改参数BLANK_TRIMMING为true
alter system set BLANK_TRIMMING=true scope=spfile;
重启数据库进行测试
进行测试
SQL> DECLARE
2 c_Plan_ID char(6);
3 BEGIN
4 SELECT cont_no INTO c_Plan_ID from abc;
5 dbms_output.put_line(c_Plan_ID);
6 END;
7 /
123456
PL/SQL procedure successfully completed
看到可以完成了
下面是METALINK的原话
SELECT containing a MIN or MAX into a CHAR variable inside a PL/SQL block Fails With ORA-06502 [ID 311653.1]
Applies to:
Oracle Server -EnterpriseEdition - Version:10.1.0.4 to 10.1.0.4
Oracle Server -EnterpriseEdition - Version:9.2.0.6 to 9.2.0.7
Oracle Server -EnterpriseEdition - Version:10.2.0.1 to 10.2.0.1
This problem can occur on any platform.
Symptoms
SELECT containing a MIN or MAX into a CHAR variable inside a PL/SQL block Fails With:
ORA-06502: PL/SQL: numeric or value error: character string buffer too small
Example:
DECLAREC CHAR(1);BEGINSELECT MIN('Y') INTO C FROM dual;END;/DECLARE*ERROR at line 1:ORA-06502: PL/SQL: numeric or value error: character string buffer too smallORA-06512: at line 4Changes
After upgrading to Oracle10gR210.2.0.1
After applying10.1.0.4 patchset
After applying9.2.0.6 patchset
After applying9.2.0.7 patchset
Cause
This problem has been identified as
Bug:4458790 ORA-6502 selecting MAX/MIN into a CHAR variable in PLSQL
This problem is introduced in Oracle9i9.2.0.6, Oracle10g10.1.0.4 and 10.2.0.1 by the fix for Bug:3499258.
A PLSQL block which SELECTs a MAX or MIN into a fixed CHAR variable can fail with an unexpected ORA-6502 "character string buffer too small" error.
Solution
This problem is fixed in
Oracle9iR2 (9.2.0.8, terminal patchset)
Oracle11gR1(11.1.0.x or higher)
Oracle10gR1(10.1.0.5 or higher)
Oracle10gR2 (10.2.0.2 or higher)
Workarounds:
setting initialisation parameter BLANK_TRIMMING=TRUE
declare PL/SQL CHAR and VARCHAR2 variable used in the INTO clause of SELECT statement as 4,000 bytes.
Use CAST SQL function to constraint the size to that of the variable size like
SELECT CAST(MIN('Y') AS CHAR(1)) INTO C FROM DUAL;
selectto_char(max(RENEWAL_DATE)) intoM_YEAR_MONTH fromt_renewal_schedule;
ORA-06502: PL/SQL:数字或值错误: 字符串缓冲区太小
这个时候有3个方法可以解决
1、setting initialisation parameter BLANK_TRIMMING=TRUE
2、declare PL/SQL CHAR and VARCHAR2 variable used in the INTO clause of SELECT statement as 4,000 bytes.
3、Use CAST SQL function to constraint the size to that of the variable size like
SELECT CAST(MIN('Y') AS CHAR(1)) INTO C FROM DUAL;
CAST是强制转换函数。
参数BLANK_TRIMMING设置为TRUE的时候可以解决我们的BUG问题,同时这个参数设置为TRUE会在进行变量的赋值的时候忽略末尾的空格,同时这个参数必须关闭数据库进行更改。所以请评估下,是否可行。
试验如下:
SQL> CREATE TABLE abc (
2 cont_no char(8),
3 plan_id char(7));
Table created
SQL> INSERT INTO abc VALUES ('123456 ', '7654321'); ---(这里空格有2位)
1 row inserted
SQL> commit;
SQL> DECLARE
2 c_Plan_ID char(6);
3 BEGIN
4 SELECT cont_no INTO c_Plan_ID from abc;
5 dbms_output.put_line(c_Plan_ID);
6 END;
7 /
DECLARE
c_Plan_ID char(6);
BEGIN
SELECT cont_no INTO c_Plan_ID from abc;
dbms_output.put_line(c_Plan_ID);
END;
ORA-06502: PL/SQL:数字或值错误: 字符串缓冲区太小
ORA-06512:在line 5
然后我们修改参数BLANK_TRIMMING为true
alter system set BLANK_TRIMMING=true scope=spfile;
重启数据库进行测试
进行测试
SQL> DECLARE
2 c_Plan_ID char(6);
3 BEGIN
4 SELECT cont_no INTO c_Plan_ID from abc;
5 dbms_output.put_line(c_Plan_ID);
6 END;
7 /
123456
PL/SQL procedure successfully completed
看到可以完成了
下面是METALINK的原话
SELECT containing a MIN or MAX into a CHAR variable inside a PL/SQL block Fails With ORA-06502 [ID 311653.1]
Applies to:
Oracle Server -EnterpriseEdition - Version:10.1.0.4 to 10.1.0.4
Oracle Server -EnterpriseEdition - Version:9.2.0.6 to 9.2.0.7
Oracle Server -EnterpriseEdition - Version:10.2.0.1 to 10.2.0.1
This problem can occur on any platform.
Symptoms
SELECT containing a MIN or MAX into a CHAR variable inside a PL/SQL block Fails With:
ORA-06502: PL/SQL: numeric or value error: character string buffer too small
Example:
DECLAREC CHAR(1);BEGINSELECT MIN('Y') INTO C FROM dual;END;/DECLARE*ERROR at line 1:ORA-06502: PL/SQL: numeric or value error: character string buffer too smallORA-06512: at line 4Changes
After upgrading to Oracle10gR210.2.0.1
After applying10.1.0.4 patchset
After applying9.2.0.6 patchset
After applying9.2.0.7 patchset
Cause
This problem has been identified as
Bug:4458790 ORA-6502 selecting MAX/MIN into a CHAR variable in PLSQL
This problem is introduced in Oracle9i9.2.0.6, Oracle10g10.1.0.4 and 10.2.0.1 by the fix for Bug:3499258.
A PLSQL block which SELECTs a MAX or MIN into a fixed CHAR variable can fail with an unexpected ORA-6502 "character string buffer too small" error.
Solution
This problem is fixed in
Oracle9iR2 (9.2.0.8, terminal patchset)
Oracle11gR1(11.1.0.x or higher)
Oracle10gR1(10.1.0.5 or higher)
Oracle10gR2 (10.2.0.2 or higher)
Workarounds:
setting initialisation parameter BLANK_TRIMMING=TRUE
declare PL/SQL CHAR and VARCHAR2 variable used in the INTO clause of SELECT statement as 4,000 bytes.
Use CAST SQL function to constraint the size to that of the variable size like
SELECT CAST(MIN('Y') AS CHAR(1)) INTO C FROM DUAL;
相关文章推荐
- Hibernate createSQLQuery 查询Oracle char类型结果为一个字符解决方法汇总
- SQLQuery 查询Oracle char类型返回一个字符有关问题
- Hibernate SQLQuery 查询Oracle char类型结果为一个字符的解决方法
- Oracle 有long类型字段的表 使用insert into select 语句 ,出现:ORA-00997 错误
- 解决 oracle查询时char类型为character只显示一个字符的问题
- SQLQuery 查询Oracle char类型返回一个字符问题
- 【C语言】编写一个函数reverse_string(char * string) 实现:将参数字符串中的字符反向排列。要求:不能使用C函数库中的字符串操作函数。
- ORACLE CHAR,VARCHAR,VARCHAR2,NVARCHAR类型的区别与使用
- (转载) socket:10038错误{winSock的一个bug:当closesocket多次错误使用时会导致问题}
- OracleCHAR,VARCHAR,VARCHAR2类型的区别与使用
- 使用bool 类型变量赋值时的一个错误
- ORACLE MAX对CHAR类型的特殊处理(V10.2.0.1.0)
- 编写一个函数reverse_string(char * string) 实现:将参数字符串中的字符反向排列。 要求:不能使用C函数库中的字符串操作函数
- 电话号码处理,附错误类型(无效字符,plsql该sql中不允许使用函数)
- Oracle CHAR,VARCHAR,VARCHAR2,nvarchar类型的区别与使用
- Oracle CHAR,VARCHAR,VARCHAR2类型的区别与使用
- oracle中使用impdp数据泵导入数据提示“ORA-31684:对象类型已经存在”错误的解决
- 编写一个函数reverse_string(char * string)(递归实现) 实现:将参数字符串中的字符反向排列。 要求:不能使用C函数库中 的字符串操作函数。
- Oracle CHAR,VARCHAR,VARCHAR2,nvarchar类型的区别与使用
- java中一个char类型字符能表示世界上所有语言的所有字符吗?