Java如何读取配置文件

1.在Java工程中新建一个Package:com.test.common,在包下新建一个CommonParam类，代码如下：

package com.test.common;

import java.util.MissingResourceException;

import java.util.ResourceBundle;

public class CommonParam {

    private String propertyFileName;

    private ResourceBundle resourceBundle;

    public CommonParam() {

        propertyFileName = "com/test/common/SysConfig";

        resourceBundle = ResourceBundle.getBundle(propertyFileName);

    }

    public String getString(String key) {

        if (key == null || key.equals("") || key.equals("null")) {

            return "";

        }

        String result = "";

        try {

            result = resourceBundle.getString(key);

        } catch (MissingResourceException e) {

            e.printStackTrace();

        }

        return result;

    }

}

2.在包com.test.common下新见一个SysConfig.properties文件，格式如下：

userName=test

password=test

3.编写测试类Test，代码如下：

package com.test.common;

public class TestGetPropertyValue {

    /**

     * @param args

     */

    public static void main(String[] args) {

        // TODO Auto-generated method stub

        String uName="";

        String pWord="";

        CommonParam cp = new CommonParam();

        uName= cp.getString("userName");

        pWord=cp.getString("password");

        System.out.println("---------------"+uName);

        System.out.println("---------------"+pWord);

    }

}