深入理解Oracle索引(17)：Cost 值相同 CBO 对索引的选择

     规则如下：

                     


     测试如下：

hr@ORCL> drop table t purge;

Table dropped.

hr@ORCL> create table t as select * from dba_objects;

Table created.

hr@ORCL> alter table t add (object_id_1 number);

Table altered.

hr@ORCL> update t set object_id_1=object_id;

50363 rows updated.

hr@ORCL> commit;

Commit complete.

hr@ORCL> create index idx_t_a on t(object_id);

Index created.

hr@ORCL> create index idx_t_b on t(object_id_1);

Index created.

/* 统计信息相同、意味着同类型执行计划的Cost值会相同*/
hr@ORCL> exec dbms_stats.gather_table_stats(ownname=>'HR',tabname=>'T',estimate_percent=>100,cascade=>TRUE,no_invalidate=>false);

PL/SQL procedure successfully completed.

/* 叶子块数量相同、CBO按字母顺序在前走索引*/
hr@ORCL> select index_name,leaf_blocks from user_indexes where table_name='T' and index_name in ('IDX_T_A','IDX_T_B');

INDEX_NAME LEAF_BLOCKS
------------------------------ -----------
IDX_T_A 111
IDX_T_B 111

hr@ORCL> set autot trace exp
hr@ORCL> select * from t where object_id=1000 and object_id_1=1000;

Execution Plan
----------------------------------------------------------
Plan hash value: 1194865126

---------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 98 | 2 (0)| 00:00:01 |
|* 1 | TABLE ACCESS BY INDEX ROWID| T | 1 | 98 | 2 (0)| 00:00:01 |
|* 2 | INDEX RANGE SCAN | IDX_T_A | 1 | | 1 (0)| 00:00:01 |
---------------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

1 - filter("OBJECT_ID_1"=1000)
2 - access("OBJECT_ID"=1000)

/* 把idx_t_b叶子块数量从111改为110*/
hr@ORCL> set autot off
hr@ORCL> exec dbms_stats.set_index_stats(ownname=>'HR',indname=>'IDX_T_B',numlblks=>110);

PL/SQL procedure successfully completed.

hr@ORCL> select index_name,leaf_blocks from user_indexes where table_name='T' and index_name in ('IDX_T_A','IDX_T_B');

INDEX_NAME LEAF_BLOCKS
------------------------------ -----------
IDX_T_A 111
IDX_T_B 110

/* Cost 值相同、CBO 选择叶子块数量较少的索引*/
hr@ORCL> set autot trace exp
hr@ORCL> select * from t where object_id=1000 and object_id_1=1000;

Execution Plan
----------------------------------------------------------
Plan hash value: 3073359464

---------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 98 | 2 (0)| 00:00:01 |
|* 1 | TABLE ACCESS BY INDEX ROWID| T | 1 | 98 | 2 (0)| 00:00:01 |
|* 2 | INDEX RANGE SCAN | IDX_T_B | 1 | | 1 (0)| 00:00:01 |
---------------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

1 - filter("OBJECT_ID"=1000)
2 - access("OBJECT_ID_1"=1000)


                    By David Lin 
                    20113-06-05 
                    Good Luck