如何在java中计算两时间的差

方法一：

DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

try

{

Date d1 = df.parse("2004-03-26 13:31:40");

Date d2 = df.parse("2004-01-02 11:30:24");

long diff = d1.getTime() - d2.getTime();

long days = diff / (1000 * 60 * 60 * 24);//代表天数

}

catch (Exception e)

{

}

方法二： SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

java.util.Date now = df.parse("2004-03-26 13:31:40");

java.util.Date date=df.parse("2004-01-02 11:30:24");

long l=now.getTime()-date.getTime();

long day=l/(24*60*60*1000);

long hour=(l/(60*60*1000)-day*24);

long min=((l/(60*1000))-day*24*60-hour*60);

long s=(l/1000-day*24*60*60-hour*60*60-min*60);

System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");

方法三：

SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

java.util.Date begin=dfs.parse("2004-01-02 11:30:24");

java.util.Date end = dfs.parse("2004-03-26 13:31:40");

long between=(end.getTime()-begin.getTime())/1000;//除以1000是为了转换成秒

long day1=between/(24*3600);

long hour1=between%(24*3600)/3600;

long minute1=between%3600/60;

long second1=between%60/60;

System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");