使用hibernate的this.getSession().createSQLQuery(sql).list();方法查询数据时出现查到的数据和想象的不一致，很是郁闷，诡异

今天 使用hibernate的this.getSession().createSQLQuery(sql).list();方法查询数据时出现查到的数据和想象的不一致的问题，郁闷我很长一段时间

执行的方法代码如下：

public List<?> findKaoHe4Data(String startDay, String endDay, String depIds) {
String sql = "SELECT t.dep_id,t.memo,"
+ "sum(case ISNUMERIC(t.chanl) when 1 then cast(t.chanl as float) else 0 end) as chanl,"
+ "sum(case ISNUMERIC(t.cail) when 1 then cast(t.cail as float) else 0 end) as cail,"
+ "sum(case ISNUMERIC(t.dianf) when 1 then cast(t.dianf as float) else 0 end) as dianf "
+ "FROM team_settle t  JOIN department d on d.dep_id=t.dep_id  JOIN department pd on d.pdep_id = pd.dep_id WHERE d.pdep_id IN ("
+ depIds + ") and settle_date >='" + startDay + "' and settle_date<='" + endDay + "' and t.memo<>'' "
+ "GROUP BY t.dep_id,t.memo,pd.show_order,d.show_order ORDER BY pd.show_order,d.show_order";
return this.getSession().createSQLQuery(sql).list();
}

截取到组合好的sql语句如下：

View Code

SELECT
t.dep_id,
t.memo,
sum(case ISNUMERIC(t.chanl)
when 1 then cast(t.chanl as float)
else 0
end) as chanl,
sum(case ISNUMERIC(t.cail)
when 1 then cast(t.cail as float)
else 0
end) as cail,
sum(case ISNUMERIC(t.dianf)
when 1 then cast(t.dianf as float)
else 0
end) as dianf
FROM
team_settle t
JOIN
department d
on d.dep_id=t.dep_id
JOIN
department pd
on d.pdep_id = pd.dep_id
WHERE
d.pdep_id IN (
'402882eb369b1a0601369b288b8e0006','402882eb369b1a0601369b28d3360007','402882eb369b1a0601369b293e820008','402882eb369b1a0601369b29efe10009','402882eb369b1a0601369b2a25b6000a','402882eb369b1a0601369b2a5e1b000b'
)
and settle_date >='2013-01-01'
and settle_date<='2013-01-16'
and t.memo<>''
GROUP BY
t.dep_id,
t.memo,
pd.show_order,
d.show_order
ORDER BY
pd.show_order,
d.show_order

拿到navcat中执行以下代码，得到的是15条记录



但是java类中 的list集合却显示的是9条记录



为什么两处的查询结果不一致呢，找不到原因，以致使用hibernate show_sql功能，在控制台打印的sql，

拿到navcat中执行以下仍然是15条记录，疯了，疯了，崩溃了，啥子原因...

疯了之后，把meyeclipse关闭了重启，还是不好使，疯了，疯了。。。

就在忽然间，看到了在navcat中执行查询的数据库是服务器的数据库，然而在项目中连接的数据库是本地的数据库，

忽然间我仰天大笑，仰天大笑，原来是这原因，疯了疯了